The base of the triangle measures 16 in.
let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
I don't know were the statement are but here are the specs of each set
Step-by-step explanation:
Set A
mean; 83.83333
median; 87.5
mode; it has no mode
range; 147
Set B
mean; 67.08571
median; 3
mode; no mode
range; 376
hope this helps sorry for late answer :)
Answer:
−33999/50
Step-by-step explanation:
2/100−680
=
1/50−680
=
−33999/50
Answer:
x = 48
Step-by-step explanation:
First find y
52+y+59 = 180 since they from a straight line
y = 180-59-52
y = 69
Then we know the angles of a triangle add to 180
x+y+63 = 180
x+69+63 = 180
x = 180-69-63
x =48
