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Umnica [9.8K]
2 years ago
10

What is the property of (4y+1)x 0=0

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
4 0

Answer:

lemme guess algebra test?

Step-by-step explanation:

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Help please ?<br> Write a quadratic equation in standard form with the given root(s) -5,1/2
sergejj [24]

Answer:

2x^2+9x-5

Step-by-step explanation:

(X+5)(x-1/2)

x^2-1/2x+5x-5/2

x^2+9/2x-5/2

multiply through by 2

2x^2+9x-5

5 0
3 years ago
Round to the merest hundredth389.993
kvasek [131]
What's a hundredth?

it's like this:

0.01

so where is the hundred place in this number?

389.9<em>9</em>3

it's the 9 that i made boldface

so to round to this number we delete everything after it, asking ourselves if the number after it is 4 or less? yes! so we can just delete it without changing anyway


389.99

3 0
2 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
2 years ago
If a neutral atom gains an electron, what is its charge?
DENIUS [597]
C. Negative because since the neutral atom stands at 0 and positive ions are 1+ and electrons are negative if it gains the electron ( negative ) it will become negative.
7 0
2 years ago
Which represents the inverse of the function f(x)=4x?
Juliette [100K]

Answer:

h(x) = \frac{1}{4}x

Step-by-step explanation:

Suppose h is the inverse of f then

f(x) = y ⇔ h(y) = x

f(x) = y ⇔ 4x = y ⇔ x = y/4

and since x = h(y) then h(y) = y/4

then we can write :

h(x) = \frac{x}{4}

______________________

:)

8 0
3 years ago
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