The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.
Answer:
ok no prob ...........lolllllll
Hey there! :D
x+56/7=11
A number plus fifty-six sevenths is equal to eleven.
I hope this helps!
~kaikers
So b/10 has to be -1, that means b is -10
107-7=90
90divided 5=18
18*5=90+17=107
I did the work ♥♥♥♥