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N76 [4]
3 years ago
7

Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot mei can use to heat all the soup? a.

2 liters b.3 liters c.1 liter d.4 liters
Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

Option B. 3 liters

Step-by-step explanation:

First, we shall determine the total volume of soup that Mei have. This is illustrated below:

Mei have 8 jars of soup containing 300mL each. Therefore, she has a total of = 8 x 300mL = 2400mL.

Next, we shall convert 2400mL to litres (L). This can be obtain as follow:

1000mL = 1L

Therefore, 2400mL = 2400/1000 = 2.4L

Mei have 2.4L of soup.

Since the total volume of the soup that Mei have is 2.4L, she will be needing a minimum of 3L pot to heat up all the soup.

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Answer:

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Step-by-step explanation:

You forgot to put the correct area model, I attached it to the answer.

We have the fact that Mountain Q is 4 times the height of Mountain P. That's the "4" we have in the left side of our model. It's like having a multiplication table, next to the "4" we have "A" and upper this we have "1000", the only thing we have to do is multiplify 4*1000=4000. The next letter we have is B and below it we have "320", we divided it by 4, 320/4=80. The last letter we have is C, and is below a "6", we only have to multiplify it by 4, 6*4=24.

At the end we only sum our

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3 years ago
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tia_tia [17]

Answer:

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Step-by-step explanation:

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