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2 years ago

Does side lengths 4, 8 and 12 form a right triangle?

Mathematics

2 answers:

NeTakaya2 years ago

7 0

Answer:

No it does not form a triangle.

Step-by-step explanation:

If the lengths satisfy the Pythagorean Theorem (a2+b2=c2) then it is a right triangle.

egoroff_w [7]2 years ago

5 0

No it doesn’t form a right triangle

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Vsevolod [243]

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3 years ago

Add 3/14+4/14 simply your answer

Mila [183]

Answer:

$\Large \boxed{\frac{1}{2}}$

Step-by-step explanation:

$\displaystyle \frac{3}{14} +\frac{4}{14}$

Add the fractions since the denominators are the same.

$\displaystyle \frac{3+4}{14}$

$\displaystyle \frac{7}{14}$

Simplifying the fraction.

$\displaystyle \frac{7(1)}{7(2)}$

$\displaystyle \frac{1}{2}$

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2 years ago

A car leaving a stop sign accelerates...what is the average speed of the car, in feet per second, equation d=1.1t^2 average spee

spayn [35]

Answer:

10.27 feet/sec.

Step-by-step explanation:

The distance traveled by the car, d in feet, is given by the function $d = 1.1t^{2}$ .......... (1), where t is the time in seconds.

So, at t= 2 sec, from equation (1) we get d = 1.1 × 4 = 4.4 feet.

Again, at t = 5 sec, we get d = 1.1 × 32 = 35.2 feet.

Now, average speed of the car from t = 2 sec. to t = 5 sec. will be give by

$\frac{\textrm {Total distance traveled}}{\textrm {Total time spent}}$

= $\frac{35.2 - 4.4}{5 - 2} = 10.27$ feet/sec. (Answer)

8 0

3 years ago

The specific gravity of a substance is the ratio of its weight to the weight of an equal volume of water. Kerosene weighs 0.82 g

netineya [11]

Answer:

The specific gravity of kerosene is 0.82

Step-by-step explanation:

Let

x -----> the weight in grams of a cubic centimeter of Kerosene

y ----> the weight in grams of a cubic centimeter of water

z ---> the specific gravity of a substance

$z=\frac{x}{y}$

we have

$x=0.82\ g\\y=1\ g$

substitute the values

$z=\frac{0.82}{1}=0.82$

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3 years ago

Read 2 more answers

2 parts compost, 6 parts potting soil for 10 kg of mix. How many kg of compost

likoan [24]

Answer:

Step-by-step explanation:

A proportion could be used.

With 2 parts of compost and 6 parts potting soil, you would end up with 8 total parts.

So it can be written as a ratio of compost to total mix, or $\frac{2}{8}$

The problem states 10 kg are needed in total, and the variable would be the amount of compost

As a ratio it would be $\frac{x}{10}$ .

Use the ratios to write a proportion.

$\frac{2}{8} = \frac{x}{10}$

Multiply both sides of the equation by 10

$\frac{20}{8} = x$

Convert to a decimal if desired.

$x=2.5$

3 0

3 years ago