Given:
The number of sides of given polygon = 4
To find the sum of the interior angles of the polygon.
Formula
The sum of interior angles of any polygon is
where, n be the number of sides of the polygon.
Now,
Taking n = 4 we get,
or,
or,
Hence,
The sum of the interior angles of the polygon is 360°.
<u>Given</u>:
The figure contains a right triangle.
The two angles of the triangle are 45° each.
The length of one leg is 3 units.
The length of the hypotenuse is x units.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the formula,
where , adj = 3 and hyp = x.
Substituting these values, we get;
Simplifying, we get;
Thus, the value of x is
1/6 - 6,12,18,24 (we counted by 6's, 2 times to get 12)
1/4 - 4,8,12,16 (we counted by 4's, 3 times to get 12)
12 is the LCD (Lowest Common Denominator) of the 2 fractions
*Now that we have the denominator, we need to find the numerator
1/12 - 1x2 (why 2? well because we had to count by 6's, 2 times to get 12)
1/4 - 1x3 (why 3? well because we had to count my 4's, 3 times to get 12)
2/12 and 3/12 is the answer
I hope you get it!!