<span>The best answer to this problem is 0.0823.
np = 48 * 1/4 = 12
The exactly 15 would be written as 14.5 to 15.5. You then plug those into you equation separately.
e1= (14.5-12)/3 = 0.833 and e2 =(15.5 - 12)/3 = 1.167)
p(0.833<e<1.167)= 0.0808</span>
Answer:
A literary work credited with advancing ancient Indian civilization because it set rules for the organization of Buddhist monasteries.
Step-by-step explanation:
we are given the expression (4e) ^x and is asked to derive the expression. we distribute first the equations resulting to 4^x e^x = y. using the rule of products,
y = 4^x e^xy' = 4^x ln 4 e^x + 4^x e^x
The final answer is y' = 4^x ln 4 e^x + 4^x e^x
In order to solve for this question, let's assign a couple variables.
The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.
From the given, we can already form two equations:
t + s = 36
("An exam... contains 36 questions")
2t + 6s = 148
("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")
Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:
2t + 6s = 148
t + 3s = 74
Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):
t + s = 36
t = 36 - s
This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:
t + 3s = 74
(36 - s) + 3s = 74
36 + 2s = 74
2s = 38
s = 19
Input 's' into our second equation to solve for 't':
t = 36 - s
t = 36 - 19
t = 17
There are 17 two-point questions and 19 six-point questions
- T.B.
To shift a graph down by two units, -2 must beg added to the function.
Since g(x)=0.5x-k already, k=2, because it is already specified that the constant will be subtracted.
