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Anastaziya [24]

3 years ago

13

14). A Christmas tree in the shape of an isosceles triangle sits on a

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

The area would be 60 feet

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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Write a conditional statement that is false but has a true inverse fast please

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If two angles are not complementary, then their angles add up to 180 degrees.

Step-by-step explanation:

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PLEASE HELP WILL MARK BRAINLIEST THANK YOU

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write an expression for add 2 and 4 and multiply the sum by 3 next add 5 to that product in double the results

Rzqust [24]

So let's start from the beginning.

Add 2 and 4:

(2 + 4)

Multiply the sum by 3:

3(2 + 4)

Then add 5 to that product:

3(2 + 4) + 5

Then double the results:

2[3(2 + 4) + 5]

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