The given formula above, y = -x, is a sample of a function. A function is an equation that would give only one value of y for every value of x. This is the same as saying that exactly one output is set by each input. If we take x = -1, the value of y is 1 and nothing else.
we can always find the slope of any line by simply using two points on the line, say let's use (3,4) and (-1,2)

A variable with a fraction exponent can be rewritten using a radical.
The equations would be A. radical equation
Answer:
The correct option is D)
.
Step-by-step explanation:
Consider the provided cubic function.
We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.
A "zero" of a given function is an input value that produces an output of 0.
Substitute the value of zeros in the provided options to check.
Substitute x=-2 in
.

Therefore, the option is incorrect.
Substitute x=-2 in
.

Therefore, the option is incorrect.
Substitute x=-2 in
.

Therefore, the option is incorrect.
Substitute x=-2 in
.

Now check for other roots as well.
Substitute x=√2 in
.

Substitute x=-√2 in
.

Therefore, the option is correct.