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4 years ago

NEED HELP WITH THIS PROBLEM!!!!!!

Mathematics

1 answer:

zzz [600]4 years ago

3 0

Answer:

$\displaystyle\frac{\sqrt[4]{3x^2}}{2y}$

Step-by-step explanation:

It can work well to identify 4th powers under the radical, then remove them.

$\displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}$

_____

The applicable rules of exponents are ...

1/a^b = a^-b

(a^b)(a^c) = a^(b+c)

The x-factors simplify as ...

x^6/x^4 = x^(6-4) = x^2

The y-factors simplify as ...

y/y^5 = 1/y^(5-1) = 1/y^4

The constant factors simplify in the usual way:

24/128 = (8·3)/(8·16) = 3/16

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Which table of values best represents the following verbal description?

pishuonlain [190]

Answer: D or the one on the bottom right

Step-by-step explanation:

Because first we know 0^2 will still be 0 so we look for one that has -9 and so we can already eliminate A and B (the ones on the left)

Next, take 2^2 for example that is 4 then you minus 9 from that and get -5 so find the table with X = 2 Y = -5 and that would be D so that is your answer!

Hope this helps! LMK if you need more help/ have more questions!

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2 years ago

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3 years ago

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Alinara [238K]

Answer:

Step-by-step explanation:

$3x - 5 = -2x + 10$

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3 years ago

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$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{1-\sin^2(t)}$

Recall that $\cos^2(x)+\sin^2(x)=1$ for all x :

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{\cos^2(t)}$

If $\cos(t)\neq0$ , we can cancel a factor of it in the second fraction.

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3 years ago

X+4z-5-3x when x=2 z=3x

kati45 [8]

Answer:

Step-by-step explanation:

Since we know x = 2 and z = 3x, let's find z by substituting the value for x into z:

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Now that we have the values of both x and z, we can substitute them into the expression and simplify:

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3 years ago