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1 year ago

(gof)(x) = x2 + x + 1

Mathematics

1 answer:

Sever21 [200]1 year ago

8 0

Answer:

$the \: answer \: is \: b$

Step-by-step explanation:

$(gof)x = {(x + 1)}^{2 } = {x}^{2} + 2x + 1$

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What's the correct answer to this..? Please help

mestny [16]

Answer:

D. {x:-8≤x<-5}

Step-by-step explanation:

x≥-8

x={-8,-7,-6,-5,-4,-3,-2,-1,0...}

x<-5

x={-6,-7,-8,-9,-0...}

Numbers equal to or less than -8 are also less than -5

Hope it helps ;) ❤❤❤

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2 years ago

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Answer for brainliest what is the volume

lisov135 [29]

Answer:

The answer is 36

Step-by-step explanation:

To find the volume you:

$multiply \: (6 \times 3 \times 2) = 36{cm}^{3}$

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1 year ago

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Which fraction does point P represent on the number line below?

yarga [219]

The answer is C because it is at the first of four intervals between 0 and 1

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2 years ago

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In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

vichka [17]

Answer:

$x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-10 and c=6

Putting values in the quadratic formula

$x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}$

So, $x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

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2 years ago

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Use a half-angle identity to find the exact value of tan 22.5°.

dusya [7]

Answer:

$\sqrt{2} -1$

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: $tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }$

We need just the values of:

$sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}$

and of

$cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}$

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

$tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1$

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2 years ago

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