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neonofarm [45]
3 years ago
13

Only 3 alligators can Set at the round table

Mathematics
1 answer:
user100 [1]3 years ago
8 0
What is the problem? I don't understand
You might be interested in
Why in division there is sometimes remaindres?
Ksenya-84 [330]
In division problems, if the division results in a decimal or fraction, (not a whole number), than it has a remainder.  If the division results in a whole number, then there is no remainder, or a remainder of zero. 

Examples:

6/3=2

6/4=1.5
7 0
3 years ago
Read 2 more answers
A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 20 componen
musickatia [10]

Answer: Probability that this whole shipment will be accepted is 0.629

Step-by-step explanation:

The company randomly select and test 20 components and accept the whole batch if there are fewer than 3 defectives.

Applying normal distribution,

z = (x-u)/s

Where

n = number of components that were tested.

s = standard deviation

u = mean = np

p = probability that the component has defect

q = probability that the component does not have defect

x = r = the number of components

From the information given,

p = 8/100 = 0.08

q = 1-q = 1-0.08 = 0.92

n = 20

u = 20×0.08 = 1.6

s = √20 × 0.08 × 0.92 = √1.472

s = 1.21

Probability that this whole shipment will be accepted will be probability that fewer than 3 components have defects. This means that it must be lesser than or equal to 2 components.

P(x lesser than 3) =P(x lesser than or equal to 2). Therefore,

x = 2

z = (2-1.6)/1.21 = 0.33

Looking at the normal distribution table, the corresponding z score is 0.629

8 0
3 years ago
Automobile racing, high-performance driving schools, and driver education programs run by automobile clubs continue to grow in p
yuradex [85]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X₁: Weight of a safety helmet for racers

X₂: Price of a safety helmet for racers

Note, there is n= 17 observed values for each variable so for all calculations I'll use this number and disregard the 18 mentioned in the text.

a) Scatterplot in attachment.

b) If you look at the diagram it seems that there is a negative linear regression between the price and the weight of the helmets, meaning, the higher the helmet weights, the less it costs.

c) The estimated regression equation is ^Yi= a + bXi

n= 17; ∑Y= 6466; ∑Y²= 3063392; ∑X= 1008; ∑X²= 60294; ∑XY= 367536

Y[bar]= 380.35; X[bar]= 59.29

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{367536-\frac{1008*6466}{17} }{60294-\frac{(1008)^2}{17} } = -30.18

a= Y[bar]- bX[bar]= 380.35-(-30.18)*59.29= 2169.77

The estimated regression equation for the price of the helmets as a function of their weight is:

^Yi= 2169.77 -30.18Xi

I hope it helps!

8 0
3 years ago
Solve the equation -4(8+y)=90.
Delvig [45]

Answer:

-32+y+90

y=122

Step-by-step explanation:

8 0
3 years ago
At the end of the day, a bakery gives everything that is unsold to food banks for the needy. If it has 12 apple pies left at the
juin [17]

Answer:

462 ways

Step-by-step explanation:

The formula to use in solving this problem is given as the Combination formula

The Combination formula is given as

C(n , r) = nCr = n!/r! (n - r)!

We are told that a food bakery has 12 pies unsold at the end of the day which they intend to share to 6 food banks

n = 12, r = 6

In order to ensure that at least 1 food bank gets 1 pie, we have:

n - 1 = 12 - 1 = 11

r - 1 = 6 - 1 = 5

Hence,

C(11, 5) = 11C5

= 11!/ 5! ×(11 - 5)!

= 11!/5! × 6!

= (11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)/ (5 × 4 × 3 × 2 × 1) ×( 6 × 5 × 4 × 3 × 2 × 1)

= 462 ways

3 0
3 years ago
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