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vitfil [10]
3 years ago
14

7 + 2X = 5 3 ..... zzzzzzzz

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

23

Step-by-step explanation:

please mark brainliest

Elan Coil [88]3 years ago
4 0

Answer:

x = 23

Step-by-step explanation:

7 + 2x = 53

7 + 2x - 7 = 53 - 7

2x = 46

2x / 2 = 46 / 2

x = 23

Hope this helps

Maybe brainliest?

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A dfc is equal to bfc and that is a fact

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Which shows another way to write 64?
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None of those show another way to 64

6*6*6*6=1296

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6+6+6+6=24

6*4=24

Another way to show 64 is 8*8 or 4^3

4 0
3 years ago
What is the GCD of 18 and 48
JulijaS [17]

Answer:

6

Step-by-step explanation:

So the greatest common factor 18 and 48 is 6.

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2 years ago
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Scores on a statewide standardized test are normally distributed with a mean of 12.89 and a standard deviation of 1.95. Certific
Ulleksa [173]

Answer:

Marcus score is 13.7, the mean is 12.89, and the standard deviation is 1.95, so I’ll do ( 13.7 – 12.89)/ 1.95, Since Marcus' z-score is 0.415. The area to the left of the z-score is 65.9% so therefore Marcus did scored better than 65.9% of the students. So Marcus needs to score 98% better of all the other students in order for him to receive an actual certificate.

Step-by-step explanation:

4 0
3 years ago
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
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