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3 years ago

11

I will share to explain how to convert 22 inches to feet. (how can you do it, what is important about setting up proportions, wh

at sheet can we use to help is with conversions)

2 answers:

AnnZ [28]3 years ago

8 0

1 foot and 10 inches?

navik [9.2K]3 years ago

6 0

12 inches is in 1 foot.

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A small fountain holds 38 gallons of water in 4 equal-sized sections.

NemiM [27]

A 38/4
B 9 2/4
C 9 1/2

5 0

2 years ago

Share 1200kg in the ratio 3:37

bearhunter [10]

Answer:

3+37=40

3/40×1200=90kg

37÷40×1200=1110kg

Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

Mr. Inahurry sold his house for $27,000, which is a 10% loss over what he originally paid for it. What did he pay for the house

Ainat [17]

Answer: $30,000

Step-by-step explanation:

If Mr. Inahurry had a 10% loss, it means that he paid X for the house and only got back 90% (100% - 10%) of what he paid.

This way X . 90% = 27,000

X . 0.90 = 27,000

X = 27,000/0.9

X = 30,000

Counter-proof: 30,000 . 10% = 30,000 . 0.10 = 3,000

30,000 - 3,000 = 27,000

4 0

2 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

What is the measure of ∠S ?

jeka94

Alright, lets get started.

We could use sine law to find the remaining angle.

$\frac{sinA}{a} = \frac{sinB}{b}$

$\frac{sinS}{63.6} = \frac{sin64}{69.8}$

Plugging the value of sin 64

$\frac{sinS}{63.6} = \frac{0.8987}{69.8}$

$\frac{sinS}{63.6} = 0.01287$

Cross multiplying

sin S = 0.8189

Taking inverse on both side

$S = sin^{-1}(0.8189)$

S = 55° : Answer

Hope it will help :)

4 0

3 years ago

Read 2 more answers