The equation represents height as a function of time.
The bullet was in the air for 75 seconds.
The equation is given as:
The time spent in the air is the time it takes the bullet to land on the ground.
When the bullet is on the ground, the height is:
So, we have:
Factor out t
Split
or 
represents when the shot is fired.
So, we solve for t in
Collect like terms
Divide both sides by 16
Hence, the bullet was in the air for 75 seconds
Read more about height and time at:
brainly.com/question/2261757
My answer is 16 cause if you add 10 and 3 and 3 the =16
After the first three days, the sample size will be half of the initial; therefore, 400g/2= 200g. However, it is asking how long will it take to decay to 100g, so we will take 200g/2= 100g, which will take another three days. It will take 2 half-lives, which will encompass 6 days.
Answer:
Third quartile (Q₃) = 46.75 minutes.
Therefore, Option (c) is the correct answer.
Step-by-step explanation:
Given: Mean (μ) = 40 minutes and S.D (σ) = 10 minutes
To find : Third quartile (Q₃) = ?
Sol: As the third quartile of normal distribution covers the 75% of the total area of the curve and first quartile covers the 25% of the total area of the curve. Then with the help of z score table, the value represented the third quartile of the normal distribution is:
Q₃ = μ + 0.675 σ
Now by substitution the value of mean and standard deviation,
Q₃ = 40 + 0.675 × (10)
Q₃ = 40 + 6.75
Q₃ = 46.75
Therefore, the third quartile (Q₃) = 46.75. So, option (c) is the correct answer.
Answer:
e=2
Step-by-step explanation:
multiply both sides by 2 to get the variable by itself.
e=6
