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4 years ago

For which of the following molecules does shape have an effect on its ability to carry oxygen?

Chemistry

2 answers:

vova2212 [387]4 years ago

5 0

D. Hemoglobin carries oxygen (it is the only one in this list that does.)

dusya [7]4 years ago

5 0

Correct answer: D. Hemoglobin

The protein hemoglobin has four polypeptide chains, each one bound to a heme group. Each hemoglobin molecule can carry four oxygen molecules because of the presence of four heme groups. The binding of the first oxygen molecule modifies the shape of hemoglobin molecule slightly, this helps in increasing the oxygen binding capacity of the hemoglobin molecule. So, this alteration in shape increases the oxygen carrying capacity of the hemoglobin molecule.

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2) C_H,(g) + 30,(g) → 2 CO2(g) + 2 H2O(g)

nalin [4]

Answer:

a. 2.7 mol of water

b CH2.

c. O2

Explanation:

The complete equation of the reaction should be:

2CH2(g) + 3O2(g) → 2 CO2(g) + 2 H2O(g)

a) how many moles of water will be made?

To make 2 molecules of water (H2O) we need 2 molecules of CH and 3 molecules of O2.

We have 2.7 mol of CH2, the possible yield of water produced if it all used up will be:

2.7 mol * 2/2= 2.7 mol

We have 6.3 mol of O2, the possible yield of water produced if it all used up will be:

6.3 mol * 2/3 = 4.2 mol

Since the maximum yield of CH2 lower, we can have 2.7 mol of water and have some excess oxygen at the end of the reaction.

b) What is the limiting reactant?

A limiting reactant is a reactant that will be used up in the reaction. This reactant has the lowest stoichiometric ratio compared to other reactants, which make them the one depleted out first. Since they depleted, the reaction will stop. Thus they limit the number of reactions and called limiting reactants. If you add the limiting reactant, the reaction will continue.

The limiting reactant in this reaction is the CH2. When producing water molecules, all 2.7 mol of CH2 will be used while we still have O2 left.

c) What is the excess reactant?

The excess reactant will have some remains after the reaction stop. That is because the excess reactant has more mass than needed for the reaction that will use all limiting reactants. Since we still have remains, adding excess reactant won't continue the reaction.

The excess reactant in this question is O2 since it still has remained after we make 2.7 mol of water. The O2 remaining, in this case, will be:

6.3 mol - 2.7mol * 3/2= 2.25 moles

8 0

3 years ago

If the gas in the piston above has a volume of 20.0 L at a temperature of 25 C what is the volume of that gas when it is heated

dexar [7]

Answer:

15.98 L

Explanation:

First, you need to find T1, T2, V1 and V2.

T1 = 25 C = 298.15 K (25C + 273.15K)

T2 = 100 C = 373.15 K (100C + 273.15K)

V1 = 20. L

V2 = ? (we are trying to find)

Next, rearrange to fit the formula

V2 = V1 x T1 / T2

Next, fill in with our numbers

V2 = 20. L x 298.15 K / 373.15 K

Do the math and you should get...

15.98 L

- If you need more help or futher explanation please let me know. I would be glad to help!

8 0

3 years ago

Read 2 more answers

ANSWER THIS WORKSHEET ALSO I WILL GIVE BRAINIEST

aev [14]

Answer:

5. An element's mass number tells the number of protons in its nucleus.

Atomic

6. Negatively charged particles in an atom are called electrons.

True

7. The cloud model of the atom describes the location of electrons as specific orbits around the nucleus.

Bohr

8. Atoms with the same number of protons but different numbers of neutrons are called isomers.

Isotopes

9. The sum of the protons and neutrons in an atom is called the atomic number.

Mass

10. An object that helps explain ideas about the natural world is called a model.

True

11. Mendeleev arranged his periodic table in order of increasing atomic number.

Mass

12. The rows in the periodic table are called periods.

True

13. Moving across the periodic table from left to right, one finds, in order, metals, then gases, then nonmetals.

Metalloids

14. Another name for a period is a family.

Group

15. On the periodic table, elements in the same column have similar properties.

True

Explanation:

4 0

3 years ago

Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa

Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

$N_2(g)+3F_2(g)\rightarrow 2NF_3(g)$

A sample contains 19.3 g of $N_2$ is reacted with 19.3 g of $F_2$ . Now we need to find the amount of $NF_3$ that can be formed by the complete reactions of each of the reactants.

If all of the $N_2$ was used up in the reaction, how many moles of $NF_3$ would be produced?

<u>Answer:</u> 1.378 moles of $NF_3$ are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, $N_2$ is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of $N_2$ = 19.3 g

Molar mass of $N_2$ = 28.02 g/mol

Putting values in equation 1:

$\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol$

For the given chemical reaction:

$N_2(g)+3F_2(g)\rightarrow 2NF_3(g)$

By the stoichiometry of the reaction:

1 mole of $N_2$ produces 2 moles of $NF_3$

So, 0.689 moles of $N_2$ will produce = $\frac{2}{1}\times 0.689=1.378mol$ of $NF_3$

Hence, 1.378 moles of $NF_3$ are produced in the reaction.

8 0

3 years ago

What elements are formed by stars having a mass greater than eight suns?

Hoochie [10]

An elements like helium and Boron are formed by stars having a mass of one to eight suns. The example elements that are formed by stars having a mass of one to eight suns are helium and boron. The stars normally turns into a white dwarf when the mass of the stars are less than 5 times the mass of the sun.

5 0

3 years ago