1 millimeter (ml) is equal to 0.1 centimeters (cm), so all you have to do is take however many mm you have, and multiply that by 0.1. Then you have your answer. So, 59 times 0.1 is 5.9
~Silver
Answer:
Collecting residue samples.
Explanation:
All the other given options are equally important on the exploration of a bomb aftermath.
The most important task is the collection of residue samples since it needs highly skilled personel to collect accurate samples for later on analysis.
Identification of meaningful collection areas is a technical skill that requires the most experienced team memebers.
<u>Answer:</u>
<u>For 1:</u> The mass of in the original mixture is 10.46 g
<u>For 2:</u> The mass of in the original mixture is 21.11 g
<u>Explanation:</u>
We are given:
Mass of water = 1.90 g
Mass of carbon dioxide = 13.64 g
Mass of oxygen = 4.10 g
The given chemical reaction for decomposition of follows:
By Stoichiometry of the reaction:
of oxygen is produced when of potassium chlorate is decomposed.
So, 4.10 g of oxygen will be produced when = of potassium chlorate is decomposed.
Amount of in the mixture = 10.46 g
The given chemical reaction for decomposition of follows:
By Stoichiometry of the reaction:
18 g of water is produced when of potassium bicarbonate is decomposed.
So, 1.90 g of water will be produced when = of potassium bicarbonate is decomposed.
Amount of in the mixture = 21.11 g
Answer:
The answer is
<h2>720 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume = 225 mL
density = 3.2 g/mL
The mass is
mass = 3.2 × 225
We have the final answer as
<h3>720 g</h3>
Hope this helps you