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1 year ago

How many molecules are in 3.5 moles of hydrogen

Chemistry

1 answer:

jek_recluse [69]1 year ago

7 0

Answer:3.5 moles * 6.02 X 10^23 particles/mole * 2 H atoms/particle of H2 = 42.14 X 10^^23 atoms

Explanation:

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Please with this problem

olasank [31]

<h3>Answer:</h3>

Empirical Formula = C₃H₈O₃

Molecular Formula = C₃H₈O₃

<h3>Solution:</h3>

Data Given:

Mass of Sample = 9.2 g

Mass of Carbon = 3.6 g

Mass of Hydrogen = 0.8 g

Mass of Oxygen = 9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

Moles of C = Mass of C ÷ At.Mass of C

Moles of C = 3.6 ÷ 12.01

Moles of C = 0.2997 mol

Moles of H = Mass of H ÷ At.Mass of H

Moles of H = 0.8 ÷ 1.01

Moles of H = 0.7920 mol

Moles of O = Mass of O ÷ At.Mass of O

Moles of O = 4.8 ÷ 16.0

Moles of O = 0.3000 mol

Step 2: Find out mole ratio and simplify it;

C H O

0.2997 0.7920 0.3000

0.2997/0.2997 0.7920/0.2997 0.3000/0.2997

1 2.64 1.001

Multiply by 3,

3 7.92 ≈ 8 3

Hence, Empirical Formula = C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

Molecular Formula = n × Empirical Formula ---- (1)

Also, n is given as,

n = Molecular Weight / Empirical Formula Weight

Molecular Weight = 92 g.mol⁻¹

Empirical Formula Weight = 12 (C₃) + 1.01 (H₈) + 16 (O₃) = 92.08 g.mol⁻¹

So,

n = 92 g.mol⁻¹ ÷ 92 g.mol⁻¹

n = 1

Putting Empirical Formula and value of "n" in equation 1,

Molecular Formula = 1 × C₃H₈O₃

Molecular Formula = C₃H₈O₃

7 0

3 years ago

Need help on #1 thank youu!

Juliette [100K]

Oil , water , wood im pretty sure

4 0

3 years ago

Read 2 more answers

An isotope contains 26 protons, 24 electrons and 32 neutrons what is the identity of the isotope?

Tema [17]

Hey there!

26 protons + 32 neutrons = 58

26 protons means the element is iron, which is Fe.

Find the charge by finding the difference between protons and electrons.

26 - 24 = 2 (+)

We have 58, Fe, and 2+.

Your answer is 58Fe2+.

Hope this helps!

3 0

3 years ago

E/St90 232 USDR11ESEnvestorite

alina1380 [7]

Use Socratic or quiz let it help

7 0

3 years ago

The below reaction is carried out by mixing 7 g pure

Mila [183]

Answer:

$NH_4Cl$

Explanation:

Let's write the reaction occurring upon mixing calcium hydroxide and ammonium chloride:

$Ca(OH)_2 (aq)+2 NH_4Cl(aq)\rightarrow CaCl_2(aq)+2 NH_3(g)+2 H_2O(l)$

Now let's find moles of each reactant. In order to find moles, let's divide mass of each reactant by its molar mass:

$n_{Ca(OH)_2}=\frac{7 g}{74.093 \frac{g}{mol}} =0.0945 mol\\n_{NH_4Cl}=\frac{7 g}{53.491 \frac{g}{mol}}= 0.131 mol$

Now, to find the limiting reagent and the reagent in excess, we need to take these amounts and divide by the stoichiometric coefficients present in the equation to find equivalents. Calcium hydroxide has a coefficient of '1', while ammonium chloride has '2', therefore:

$eq._{Ca(OH)_2}=\frac{0.0945 mol}{1} =0.0945 mol$

$eq._{NH_4Cl}=\frac{0.131 mol}{2} =0.0655 mol$

When we have our equivalents, we find the lower one to identify our limiting reactant. Ammonium chloride has a lower equivalent than calcium hydroxide, so it's our limiting reagent, while a reagent with a higher equivalent is the one in excess.

6 0

3 years ago