Answer: secondary structure
Explanation:
<u>Answer:</u> The concentration of sulfate ions in the solution is 0.0522 M
<u>Explanation:</u>
To calculate the the molarity of solution:, we use the equation:

Given mass of alum = 2.17 g
Molar mass of alum = 478.39 g/mol
Volume of solution = 175 mL
Putting values in above equation, we get:

The chemical equation for the ionization of alum follows:

1 mole of alum produces 1 mole of potassium ions, 1 mole of aluminium ions, 2 moles of sulfate ions and 12 moles of water
So, concentration of sulfate ions = 
Hence, the concentration of sulfate ions in the solution is 0.0522 M
Molarity is defined as the number of moles of solute in volume of 1 L solution.
the molarity of KOH solution to be prepared is 0.500 M
the volume of solution to be prepared is 250 mL
the number of KOH moles in 1 L - 0.500 mol
therefore number of KOH moles in 250 mL - 0.500 mol/L x 0.250 L = 0.125 mol
Mass of KOH in 0.125 mol - 0.125 mol x 56.10 g/mol = 7.01 g
The mass of KOH required to make the solution is therefore 7.01 g
I think it is Molar masses of compounds involved or Oxidation numbers, but you can choose one of them. Or you can think about the question carefully.
7.25 x 10 , Hope this helps out.