The molarity of the resulting solution obtained by diluting the stock solution is 3 M
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 15 M
- Volume of stock solution (V₁) = 500 mL
- Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
- Molarity of diluted solution (M₂) =?
<h3>How to determine the molarity of diluted solution </h3>
M₁V₁ = M₂V₂
15 × 500 = M₂ × 2500
7500 = M₂ × 2500
Divide both side by 2500
M₂ = 7500 / 2500
M₂ = 3 M
Thus, the volume of the resulting solution is 3 M
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The answer to this is t<span>he atom is mostly empty space.</span>
The percentage of CO2 increased 48 percent. Hope this helped!
Answer:
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- <u><em>Concentrated</em></u>
Explanation:
Concentration measures the amount of solute in a solution. There are many expressions of concentration. Some of then are percentage (mass/mass, volume/mass, volume/volume), molarity, molality, mole fraction, among others.
When a solution has a high concentration it is said that it is <em>concentrated; </em>when a solution has a low concentration is is said that is is diluted.
Concentrated solutions expressed in percentage typically have about 80 - 90% (or more) of solute.
Diluted solutions expressed in percentage, tipylcally have about 10% - 20% or less.
But they are not fixed limits. You might say that a 85% solution is concentrated. Acids at 75 % sure are concentrated.
Hence, a 93.3% solution is concentrated, definitely.
Answer: This is because the number of shell increases .
Explanation: On moving from left to write on the periodic table the reactivity of non metals increases because number of shells increases and the force with which the nucleus hold electrons decreases.
