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snow_tiger [21]
3 years ago
15

Can someone please help me with this!!! pleasee

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}

Step-by-step explanation:

Q6.

\sin\theta=\dfrac{opposite}{hypotenuse}

We have

opposite=14\\\\hypotenuse=18

Substitute:

\sin X=\dfrac{14}{18}=\dfrac{14:2}{18:2}=\dfrac{7}{9}=0.777...\approx0.778

Q7.

Use sine.

We have

opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431

Substitute:

\dfrac{x}{8}=0.7431               <em>multiply both sides by 8</em>

x=5.9448\to x\approx5.9

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