Question

Can someone please help me with this!!! pleasee

Answer 1

Answer:

$\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}$

Step-by-step explanation:

Q6.

$\sin\theta=\dfrac{opposite}{hypotenuse}$

We have

$opposite=14\\\\hypotenuse=18$

Substitute:

$\sin X=\dfrac{14}{18}=\dfrac{14:2}{18:2}=\dfrac{7}{9}=0.777...\approx0.778$

Q7.

Use sine.

We have

$opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431$

Substitute:

$\dfrac{x}{8}=0.7431$               multiply both sides by 8

$x=5.9448\to x\approx5.9$