3 years ago

Can someone please help me with this!!! pleasee

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

$\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}$

Step-by-step explanation:

Q6.

$\sin\theta=\dfrac{opposite}{hypotenuse}$

We have

$opposite=14\\\\hypotenuse=18$

Substitute:

$\sin X=\dfrac{14}{18}=\dfrac{14:2}{18:2}=\dfrac{7}{9}=0.777...\approx0.778$

Q7.

Use sine.

We have

$opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431$

Substitute:

$\dfrac{x}{8}=0.7431$ <em>multiply both sides by 8</em>

$x=5.9448\to x\approx5.9$

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