1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_tiger [21]
4 years ago
15

Can someone please help me with this!!! pleasee

Mathematics
1 answer:
SVETLANKA909090 [29]4 years ago
3 0

Answer:

\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}

Step-by-step explanation:

Q6.

\sin\theta=\dfrac{opposite}{hypotenuse}

We have

opposite=14\\\\hypotenuse=18

Substitute:

\sin X=\dfrac{14}{18}=\dfrac{14:2}{18:2}=\dfrac{7}{9}=0.777...\approx0.778

Q7.

Use sine.

We have

opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431

Substitute:

\dfrac{x}{8}=0.7431               <em>multiply both sides by 8</em>

x=5.9448\to x\approx5.9

You might be interested in
In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili
frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that P(A) = \frac{12}{27}

5 students who have a cat and a dog.

This means that P(A \cap B) = \frac{5}{27}

What is the probability that a student has a dog given that they have a cat?

P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167

41.67% probability that a student has a dog given that they have a cat

6 0
4 years ago
Answer for brainliest and 10 points
umka2103 [35]

Answer:

It is rational because 121 is a perfect square.

7 0
3 years ago
Suppose a company did $3,000,000 in annual maintenance in 2013 and expects 85% of those to renew for 2014. Suppose that product
Veseljchak [2.6K]

Answer:

In year 2013 annual maintenance done = $ 3,000,000

Out of this 85% is expected to renew in 2014 = 0.85\times3000000 = $2,550,000

Now Sales in 2013 = $3,000,000

60% of these sales = 0.60\times3000000 = $1,800,000

Now out of this 60%, 20% annual maintenance was expected to be paid

In 2014 = 0.20\times1800000 = $360000

So, Total annual maintenance in 2014 = 2550000+360000

= $2,910,000

8 0
4 years ago
Is 200 cm equal 2000 m
lora16 [44]
100 cm is equal to 1000m, so yes it is equal
6 0
3 years ago
What number is a factor of 15 but not a multiple of 5
SOVA2 [1]

Answer:

Three

Step-by-step explanation:

It is not divisible by five

3 0
3 years ago
Read 2 more answers
Other questions:
  • Is it possible that the orientation of a figure could change after it has been translated? Explain.
    15·1 answer
  • Find the range of scores: 13,23,46,53, 60, 75
    10·2 answers
  • PLEASE HELP NO ONE WILL PLEASE
    10·1 answer
  • In the xy -coordinate plane, the coordinates of point s are (-2,-6), and coordinates of point T are (18,9). Point Q lies on line
    10·1 answer
  • An operator in the plant has a monthly salary of $3,200. Thirty-three percent (33%) of her salary is deducted for income tax.
    14·1 answer
  • What is this ? I need help can someone help me with this problem
    7·2 answers
  • Which theorem can you use to show that the quadrilateral on the tile floor is a parallelogram?
    6·1 answer
  • Find the volume of the sphere! Plsssss
    6·1 answer
  • Determine if the ordered pair (3,-2) is a solution of<br> 4x = 3y + 18<br> Show ALL your work here
    9·1 answer
  • Scale the numerator and the denominator down by a factor of 4 (divide) to write a fraction equivalent to 8/56. (i really need he
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!