Answer:
4, 2, 1, 2, 4
Step-by-step explanation:
-2 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-2).
f(-2) = (1/2)^-2 = 1^-2/2^-2 = 2^2/1^2 = 4/1 = 4
-1 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-1).
f(-1) = (1/2)^-1 = 1^-1/2^-1 = 2^1/1^1 = 2/1 = 2
0 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(0).
f(0) = (1/2)^0 = 1^0/2^0 = 1/1 = 1
1 > 0, so use the second equation, f(x) = 2^x, to find f(1).
f(1) = 2^1 = 2
2 > 0, so use the second equation, f(x) = 2^x, to find f(2).
f(2) = 2^2 = 4
Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8
Answer:
A
Step-by-step explanation:
perimeter of the base...
Answer:
The student's GPA is of 0.82.
Step-by-step explanation:
GPA:
To find the student's GPA, we find his weighed mean.
Grades:
7 hours worth 3(B)
6 hours worth 1(D)
20 hours worth 0(F). So

The student's GPA is of 0.82.