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Sati [7]
3 years ago
14

!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0

Answer: the answer is option c


Step-by-step explanation:


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A construction company wants to build an auditorium on a trapezium shaped plot measuring 410m2. One of the parallel sides of the
Assoli18 [71]

Answer:

other parallel side is 23m

Step-by-step explanation:

Let's assume other parallel sides as 'x'

One of the parallel sides of the trapezium plot measure 18m

so, y=18

distance between the two parallel sides measure 20m

so, h=20

now, we can use area of trapezium formula

A=\frac{1}{2}\times h \times (x+y)

now, we can plug values

A=\frac{1}{2}\times 20 \times (x+18)

we can set A=410

and then we can solve for x

410=\frac{1}{2}\times 20 \times (x+18)

10\left(x+18\right)=410

x+18=41

x=23


6 0
4 years ago
Help please will mark brainliest answer!!! ASAP!!!
dezoksy [38]
P = principal (initial amount), r = rate of interest, and t = time

So, A = 3000(1+0.025)^4

Answer: $3,311.44 (approximately)
6 0
3 years ago
At a sale, books are sold at $90.75 each, which is 75 percent of the original price. What is the original price
lions [1.4K]

\frac{75}{100}  =  \frac{90.75}{x}  \\ x = \frac{90.75 \times 100}{75}  =  \frac{9075}{75}   = 121
the answer is 121
6 0
3 years ago
Help please! I have to do this math test and I dont understand ​
n200080 [17]

Answer:

y=1x+1

Step-by-step explanation:

y=1x+1 gradient= 1 and y-intersept = 1

3 0
4 years ago
At maximum speed, an airplane tracked 1720 miles against the wind in 5 hours. Flying with the wind, the plane can travel the sam
nataly862011 [7]
Recall your d = rt, distance = rate * time.

as the plane goes against the wind, the plane is not really flying at "x" mph, but is really going slower, at " x - y ", because the wind is subtracting speed from it.

likewise, when the plane is going with the wind, is not really going at "x" mph, but at " x + y ", is going faster due to the wind, thus

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the wind}&1720&x-y&5\\
\textit{with the wind}&1720&x+y&4
\end{array}
\\\\\\
\begin{cases}
1720=(x-y)5\implies \frac{1720}{5}=x-y\\\\
344=x-y\implies \boxed{y}=x-344\\
---------------\\
1720=(x+y)4\implies \frac{1720}{4}=x+y\\\\
430=x+y\implies 430=x+\left( \boxed{x-344} \right)
\end{cases}
\\\\\\
430=2x-344\implies 774=2x\implies \cfrac{774}{2}=x\implies 387=x
6 0
3 years ago
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