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Mariana [72]
2 years ago
8

Can someone help me with this :( .

Mathematics
1 answer:
andrew11 [14]2 years ago
8 0

Answer:

Which question?

Step-by-step explanation:

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What is the perimeter of this figure?
murzikaleks [220]

Answer:

6+2+3+3+3+5=22 is a correct answer

7 0
3 years ago
Group presentations are always better than solo speeches.<br><br> True<br> False
kati45 [8]

Answer:

True

Step-by-step explanation:

Its tru

7 0
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Read 2 more answers
The slope between (3, 9) &amp; (6, 12) m=
vivado [14]

Answer: m=1

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1)

Where

y2=12

y1=9

x2=6

x1=3

so plug in your values in the slop formula:

m=(12-9)/(6-3)

=3/3

=1

6 0
2 years ago
What is the first step in constructing an incenter to triangle XYZ?
Dovator [93]

Answer:

Steps for Constructing the Incenter of a Triangle

Step 1: Construct an angle bisector for one of the angles of the triangle. ... Step 2: Construct an angle bisector for another angle of the triangle. ... Step 3: Find the point where these two angle bisectors intersect.

Step-by-step explanation:

7 0
2 years ago
Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.
nadya68 [22]

Answer:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given X_(1), X_(2) ,..., X_(n) and for each observation X_i \sim N(\mu, \sigma) since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is X_(n) and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0
3 years ago
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