This is what I found, I hope it helps! Good luck with your test
Answer:
The data is skewed, and the lowest number of crackers in a package was 7
Step-by-step explanation:
Hi,
First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.
Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.
The image shows that it is <em>positively skewed with the lowest number being 7.</em>
Answer:
oh nah oh yea oh nah the answer is this the answer is that
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
We have to find least common denominator for these fractions or we just have to find the least common multiple for 15, 6 and 4
In order to find the least common multiple, we have to represent these numbers as factors of prime numbers:
15 = 3 * 5
6 = 2 * 3
4 = 2 * 2
Least common multiples will be common factors (considering that there are no more than of them in other numbers) and the uncommon factors. Then, we can write that:
2 * 2 * 3 * 5 = 60 (there are two 2's, one common 3 and an uncommon 5)
The denominator will be 60 for the least common multiples.
<span>Length = x Width = 2x
Perimeter = 2 * length + 2 * width
= 2x + 4x
= 6x
6x = 66
x = 11
</span><span>Length = x Width = 2x
Perimeter = 2 * length + 2 * width
= 2x + 4x
= 6x
6x = 66
x = 11</span>
