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Olegator [25]
2 years ago
12

Jameson pays $39.90 for 3.8 pounds of almonds. What is the price per pound of almonds? Record your answer and fill in the bubble

s on your answer document. Be sure to use the correct place value.

Mathematics
2 answers:
tatiyna2 years ago
7 0

Answer:

10.5

Step-by-step explanation:

Because he payed 39.90 for 3.8 pounds you are divided so find out so 39.90 divided by 3.8 = 10.5


kenny6666 [7]2 years ago
5 0

Answer:

The price of almonds is $ 10.5 per pounds.

Step-by-step explanation:

Given,

The price of 3.8 pounds of almonds = $ 39.90,

Thus, we can write,

3.8\text{ pounds of almonds}=\$ 39.90

\implies 1\text{ pounds of almonds}=\frac{39.90}{3.8}=\$ 10.5

Hence, the price of almonds is $ 10.5 per pounds.

Note :

10.5 can be written 0010.50

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5 0
2 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

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