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Tanya [424]
3 years ago
9

Acceleration is generally defined as the time rate of change of velocity. When can it be defined as the time rate of change of s

peed?
Physics
2 answers:
Lena [83]3 years ago
8 0

Answer:

When the velocity doesn't change its direction

Explanation:

Since velocity vector has 2 components: direction and magnitude, and speed is the velocity's magnitude. So if the velocity doesn't change its direction, we essentially use its magnitude, aka speed, to calculate the rate of change for acceleration.

Digiron [165]3 years ago
7 0

Answer:

When direction does not change or is not involved/required.

Explanation:

Acceleration is the time rate of change in velocity. This is because like velocity, acceleration is a vector quantity and has to do with change in direction. But then, a particle can still accelerate without a change in direction. In this case, acceleration can be defined as the time rate of change of speed. This is because, since direction is not involved, speed which is a scalar quantity, has nothing to do with direction.

In essence, speed and velocity are the same when direction is not involved or when direction is not changing. Therefore, in the definition of acceleration, if there are no regards for direction, speed can be used in place of velocity.

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An experiment is done to compare the initial speed of projectiles fired from high-performance catapults. The catapults are place
anzhelika [568]

Answer:1.084

Explanation:

Given

mass of Pendulum M=10 kg

mass of bullet m=5.5 gm

velocity of bullet u

After collision let say velocity is v

conserving momentum we get

mu=(M+m)v

v=\frac{m}{M+m}\times u

Conserving Energy for Pendulum

Kinetic Energy=Potential Energy

\frac{(M+m)v^2}{2}=(M+m)gh

here h=L(1-\cos \theta ) from diagram

therefore

v=\sqrt{2gL(1-\cos \theta )}

initial velocity in terms of v

u=\frac{M+m}{m}\times \sqrt{2gL(1-\cos \theta )}

For first case \theta =6.8^{\circ}

u_1=\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}

for second case \theta =11.4^{\circ}

u_2=\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}

Therefore \frac{u_1}{u_2}=\frac{\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}}{\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}}

\frac{u_1}{u_2}=\frac{1819.181\times 0.0838}{1001\times 0.1404}

\frac{u_1}{u_2}=1.084

i.e.\frac{v_1}{v_2}=1.084

4 0
3 years ago
Scientific way of thinking
noname [10]

Answer:

huh,? can you explain the question more please

7 0
3 years ago
Read 2 more answers
The magnitude of a vector can never be less than the magnitude of one of its components. Group of answer choices True False
pogonyaev

Answer:

True

Explanation:

As the formula for magnitude of a vector v and their components v_1, v_2, v_3, v_4,..., v_n is

v^2 = v_1^2 + v_2^2 + ... +v_n^2

Since v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2 \geq 0, this means the sum of them, v^2, is always greater or equal to v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2

6 0
3 years ago
A sample from of water is heated with 5000 J of energy and its temperature goes up by 6 K. What is the mass of the sample?
Dima020 [189]

Answer:

mass= 0.1993 kg

Explanation:

Using the formula c = Q / (mΔT)

8 0
3 years ago
How does the angle of incidence compare with the angle of reflection?​
S_A_V [24]

Answer:

The angle of incidence is the angle between this normal and the incident ray; the angle of reflection is the angle between this normal and the reflected ray. According to the law of reflection, the angle of incidence equals the angle of reflection.

Explanation:

:)

8 0
3 years ago
Read 2 more answers
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