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1 year ago

Part A-Circumference of a circle

Physics

1 answer:

Bezzdna [24]1 year ago

6 0

The circumference of a circle with a diameter of 10 cm is 31.4cm.

The circumference of a circle is its edge or the measurement of its entire arc.

The circumference of a circle with radius $r$ is $2\pi r$ .

The circle in question has a diameter of 10 cm.

The radius of a circle's diameter is equal to its length divided by two. Consequently, the given circle's radius is 5 cm.

If we assume that π=3.14, then the given circle's circumference will be equal to 2×π×5. Consequently, 31.4 cm is the required circumference.

As a result, a circle with a diameter of 10 cm has a 31.4 cm circumference and it has been expressed in three significant figures.

Learn more about diameter here brainly.com/question/358744

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A table tennis ball has a mass of about 2.45 g. Suppose the ball is hit across the table with a speed of 4.0 m/s. What is it’s k

cluponka [151]

Answer:

0.0196 j

Explanation:

i) The formula for kinetic energy is as follows: 0.5*m*v^2

ii) Since we have all the values all that's left is to plug them into the equation

iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000

iv) All that's left now is to plug it into the equation so:

0.5* (s.45/1000)*(4^2)

v) Lastly we add the unit joules at the end as we're talking about energy

Hope this was useful! :)

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1 year ago

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?

Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

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2 years ago

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A 7300 N elevator is to be given an acceleration of 0.150g by connecting it to a cable of negligible weight wrapped around a tur

Firlakuza [10]

Answer:

α =18.75 rad/s²

Explanation:

Given that

Acceleration a = 0.15 g

We know that g =10 m/s²

a= 0.15 x 10 = 1.5 m/s²

d= 16 cm

Radius r= 8 cm

Lets take angular acceleration =α rad/s²

As we know that

a= α r

Now by putting the values

1.5 = α x 0.08

α =18.75 rad/s²

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3 years ago

Consider an insulated tank with a volume V = 2 L is separated into two equal-volume parts by a thin wall. On the left is an idea

steposvetlana [31]

Answer

given,

V = 2 L

the left is an ideal gas at P = 100 k Pa and T = 500 K

mass is constant

$m_1 = m_2$

$\dfrac{P_1V_1}{RT_1} = \dfrac{P_2V_2}{RT_2}$

Pressure is same because it's not changing due to process

$\dfrac{V}{500} = \dfrac{2 V}{T_2}$

$T_2 = 1000\ K$

$\Delta S_{univ} = \Delta S_{sys} + (\Delta S)_{surr}$

$\Delta S_{univ} =m(C_v ln (\dfrac{T_2}{T_1}))+ R ln (\dfrac{V_2}{V_1})$

$m = \dfrac{P_1V_1}{RT_1}$

$m = \dfrac{100 \times 10^3 \times 2 \times 10^{-3}}{287\times 500}$

m = 1.39 x 10⁻³ Kg

$\Delta S_{univ} =1.39\times 10^{-3}(0.718 ln\ 2+ 0.287 ln (2)$

$\Delta S_{univ} =0.968\times 10^{-3}\ kJ/K$

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2 years ago

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alexdok [17]

Answer:

the answer is A!! 2560 J

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2 years ago

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