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lubasha [3.4K]
1 year ago
13

t is 165 cm from your eyes to your toes. you are standing 200 cm in front of a tall mirror. how far is it from your eyes to the

image of your toes?
Physics
1 answer:
Bezzdna [24]1 year ago
3 0

The distance from your eyes to the image of your toes in the mirror is 365 cm.

What is distance?
Distance as well as displacement are two key terms in mechanics that, despite having similar sounds, have distinct definitions and meanings. How much of an object's path has been covered by a moving object is measured in terms of distance. While "How much route is covered by object inside a particular direction" is measured by displacement, The main distinction between distance as well as displacement is therefore that the former is a scalar quantity while the latter is a vector quantity. Both quantities have had some similarities despite this distinction. Meters are used to measure both length and displacement (m). In this article, we'll learn further about distance as well as displacement by understanding some key ideas, such as what distance is, its mathematical definition, what displacement is, its mathematical definition, its differences, similarities, and examples.

This is because the mirror is 200 cm away from you, and the image of your toes in the mirror is 165 cm away from the mirror. Therefore, the total distance from your eyes to the image of your toes is 200 cm (distance from you to mirror) + 165 cm (distance from mirror to image of toes) = 365 cm.

To learn more about distance
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Answer:

The torque on the board = 11.8 Nm in the anti-clockwise direction

Explanation:

Please find attached the explanation to the answer given.

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6 0
3 years ago
3. A model rocket is launched straight upward at 58.8 m/s.
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Let us assume that rocket only runs in initial energy and not using its own to flying.

Also , let upward direction is +ve and downward direction is -ve .

Initial velocity , u = 58.8 m/s .

Acceleration due to gravity , g=-9.8\ m/s^2 .

Final velocity , v - = 0 m/s .

We know , by equation of motion .

v^2-u^2=2gh\\\\2gh_{max}=0^2-58.8^2\\\\h_{max}=\dfrac{0^2-58.8^2}{-2\times 9.8}\\\\h_{max}= 176.4\ m

Hence, this is the required solution .

8 0
3 years ago
A chair of weight 125 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 3
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Answer:

N = 148.10N

Explanation:

GIVEN

Weight =125 N

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angle =42°

since there is no vertical acceleration a_{y} = 0 from

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\Sigma fa_{y} = ma_{y} = 0

N-W-Fsin42\degree = 0\\\\N= W+Fsin42\\N = 125+35\times 0.66\\N = 148.10 N

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Two objects, one with a mass of 2 m and one with a mass of 4 m are attracted to each other
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3 years ago
Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
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Answer:

Δu=1300kJ/kg  

Explanation:

Energy at the initial state

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Is saturated vapor at initial pressure we have

p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)

Process 2-3 is a constant volume process

p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)

The overall in internal energy

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We replace the values in equation

Δu=u₁-u₃

=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg

Δu=1300kJ/kg  

3 0
3 years ago
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