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lubasha [3.4K]
1 year ago
13

t is 165 cm from your eyes to your toes. you are standing 200 cm in front of a tall mirror. how far is it from your eyes to the

image of your toes?
Physics
1 answer:
Bezzdna [24]1 year ago
3 0

The distance from your eyes to the image of your toes in the mirror is 365 cm.

What is distance?
Distance as well as displacement are two key terms in mechanics that, despite having similar sounds, have distinct definitions and meanings. How much of an object's path has been covered by a moving object is measured in terms of distance. While "How much route is covered by object inside a particular direction" is measured by displacement, The main distinction between distance as well as displacement is therefore that the former is a scalar quantity while the latter is a vector quantity. Both quantities have had some similarities despite this distinction. Meters are used to measure both length and displacement (m). In this article, we'll learn further about distance as well as displacement by understanding some key ideas, such as what distance is, its mathematical definition, what displacement is, its mathematical definition, its differences, similarities, and examples.

This is because the mirror is 200 cm away from you, and the image of your toes in the mirror is 165 cm away from the mirror. Therefore, the total distance from your eyes to the image of your toes is 200 cm (distance from you to mirror) + 165 cm (distance from mirror to image of toes) = 365 cm.

To learn more about distance
brainly.com/question/26550516
#SPJ4

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A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function
Sunny_sXe [5.5K]

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$v(t)=\sin (\omega t) * \cos ^2(\omega t)

To get the position equation we just need to integrate the above equation:

$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t

$\mathrm{u}=\cos (\omega \mathrm{t})

Then:

$d u=-\sin (\omega t) d t

\Rightarrow d t=-d u / \sin (\omega t)

Replacing that in our integral we get:

$\int \sin (\omega t) * \cos ^2(\omega t) d t$

$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$

Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$f(t)=\frac{\cos ^3(\omega t)}{3}+C

To find the value of C, we use the fact that f(0) = 0.

$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0

C = -1 / 3

Then the position function is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

To learn more about motion equations, refer to:

brainly.com/question/19365526

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4 0
1 year ago
You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from beh
ryzh [129]

Answer:

c. turn downward

Explanation:

From the information given:

To find the tendency of the sander;

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Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.

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