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lubasha [3.4K]
1 year ago
13

t is 165 cm from your eyes to your toes. you are standing 200 cm in front of a tall mirror. how far is it from your eyes to the

image of your toes?
Physics
1 answer:
Bezzdna [24]1 year ago
3 0

The distance from your eyes to the image of your toes in the mirror is 365 cm.

What is distance?
Distance as well as displacement are two key terms in mechanics that, despite having similar sounds, have distinct definitions and meanings. How much of an object's path has been covered by a moving object is measured in terms of distance. While "How much route is covered by object inside a particular direction" is measured by displacement, The main distinction between distance as well as displacement is therefore that the former is a scalar quantity while the latter is a vector quantity. Both quantities have had some similarities despite this distinction. Meters are used to measure both length and displacement (m). In this article, we'll learn further about distance as well as displacement by understanding some key ideas, such as what distance is, its mathematical definition, what displacement is, its mathematical definition, its differences, similarities, and examples.

This is because the mirror is 200 cm away from you, and the image of your toes in the mirror is 165 cm away from the mirror. Therefore, the total distance from your eyes to the image of your toes is 200 cm (distance from you to mirror) + 165 cm (distance from mirror to image of toes) = 365 cm.

To learn more about distance
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States that particles are attracts with every other particle. wich force is directily proportional product of two masses and inversely proportional to the distance between the centers.
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Which action will decrease the gravitational force between two objects?
WITCHER [35]

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It’s D

Explanation:

6 0
3 years ago
Three resistors, each having a resistance, R, are connected in parallel to a 1.50 V battery. If the resistors dissipate a total
ivanzaharov [21]

Answer:

The value of resistance of each resistor, R is 2.25 Ω

Explanation:

Given;

voltage across the three resistor, V = 1.5 V

power dissipated by the resistors, P = 3.00 W

the resistance of each resistor, = R

The effective resistance of the three resistors is given by;

R(effective) = R/3

Apply ohms law to determine the current delivered by the source;

V = IR

I = V/R

I = 3V/R

Also, power is calculated as;

P = IV

P = (3V/R) x V

P = 3V²/R

R = 3V² / P

R = (3 x 1.5²) / 3

R = 2.25 Ω

Therefore, the value of resistance of each resistor, R is 2.25 Ω

4 0
3 years ago
What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
laila [671]

Answer:

Work done, W = 750 joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

It moves to a distance of, d = 15 meters

We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,

W=F\times d

W=50\ N\times 15\ m

W = 750 joules

So, the work done on an object is 750 joules. Hence, this is the required solution.

4 0
3 years ago
It is known that the 10 kg pipe will roll up the ramp and not slide on the ramp when P becomes sufficiently large. Using the rol
riadik2000 [5.3K]

Answer:

65.73N

Explanation:

The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.

It is always acting up an incline plane .

Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.

The net force acting up the plane is

Fnet = P + Fm... (1)

The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet

If R = W = mgcos (theta)

and Fm = mgsin(theta)

Then mgcos theta = Fnet

mgcos (theta) = P+Fm

mgcos (theta) = P+mgsin(theta)

P = mgcos (theta) - mgsin(theta)... (2)

Given mass = 10kg

g = 9.81m/s

We can get theta from the formula;

µ = Ff/R = wsin theta/wcos theta

µ = sin theta/cos theta

µ = tan(theta)

0.3 = tan (theta)

theta = arctan0.3

theta = 16.7°

P = 10(9.81)cos16.7° - 10(9.81)sin16.7°

P = 98.1(cos16.7°-sin16.7°)

P = 98.1(0.67)

P = 65.73N

The minimum force P required to cause impending motion is 65.73N

5 0
4 years ago
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