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lutik1710 [3]
3 years ago
15

A gallon of water weighs 8 1/3 lb. How much does 1 1/5 gallon of water weigh?

Mathematics
2 answers:
ioda3 years ago
7 0
<span>A gallon of water weighs 8 1/3 lb
</span><span>1 1/5 gallon....................? lbs

</span>8 1/3 * 1 1/5
= 25/3 * 6/5
= 10 

answer : <span>1 1/5 gallon of water weighs 10 lbs</span>
IrinaK [193]3 years ago
4 0
Can you show me the work for this please ?
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HELPPPPP ME AND ILL GIVE YOU BRAINLIEST
mote1985 [20]

Answer:

s= 60

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3 0
3 years ago
Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2
Reptile [31]

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

E(x) = \sum x* P(x)

So, we have:

E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2

This gives

E(x) = 2.7

Next, calculate E(x^2) using:

E(x^2) = \sum x^2* P(x)

So, we have:

E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2

E(x^2) = 9.5

The variance is then calculated as:

Var(x) = E(x^2) - (E(x))^2

So, we have:

Var(x) = 9.5 - 2.7^2

Var(x) = 2.21

Approximate

Var(x) = 2.2

Hence, the variance of the data is 2.2

Read more about variance at:

brainly.com/question/15858152

4 0
2 years ago
Solve 2x2 + 4x = 6 by factoring.
Reil [10]

Answer:

all work is shown and pictured

5 0
4 years ago
The sampling distribution of the proportion follows the normal distribution when the values np and nq are greater than or equal
Keith_Richards [23]
I dont know. So i am sorry ask someone alse. Thanks

8 0
4 years ago
Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
Triss [41]

Answer:

The percent of students who scored below 62 is 2.3%.

Step-by-step explanation:

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is used to represent that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

Then,

  • P (-1 < Z < 1) ≈ 0.6827
  • P (-2 < Z < 2) ≈ 0.9545
  • P (3 < Z < 3) ≈ 0.9973

Given:

μ = 78

σ = 8

<em>X</em> = 62

Compute the distance between the value of <em>X</em> and <em>μ</em> as follows:

z=\frac{x-\mu}{\sigma}=\frac{62-78}{8}=-2

Use the relation P (-2 < Z < 2) ≈ 0.9545 to compute the value of P (Z < -2) as follows:

P(-2

The percentage is, 0.02275 × 100 = 2.275% ≈ 2.3%

Thus, the percent of students who scored below 62 is 2.3%.

3 0
4 years ago
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