First we must find the relative formula mass of NH3:
14+(1x3) = 17
Now we use the formula moles(n)= mass(g)/Mr
From substitution we get 34.0/17 = 2
The answer is 2M (M for Moles)
D because as he walks away the radio will get louder
There are 2 valence elcetrons
Answer:
alkenes
nucleophiles
electrophiles
syn
anti
syn and anti
Explanation:
Compounds that contain a carbon-carbon double bond are known as <u>alkenes</u>
Alkenes are electron rich; therefore, simple alkenes do not react with <u>nucleophiles</u> or bases, but will react with <u>electrophiles</u> or acids.
In the IUPAC system, an alkene is identified by the suffix -ene-
Addition reactions in which two parts Of a reagent are added to the same side of
a double bond are known as <u>syn </u>additions.
Addition reactions in which two parts of a reagent are added from opposite
sides of a double bond are called <u>anti</u> additions
Halogenation and halohydrin formation occur with <u>syn and anti</u> -additions.
Further explanations:
Compounds that contain a carbon-carbon single bond are known as alkanes. Compounds that contain a carbon-carbon double bond are known as alkenes. Compounds that contain a carbon-carbon triple bond are known as alkynes.
Nucleophiles are electron rich so they react with electron deficient centers while Electrophiles are electron deficient so they react with electron rich centers.
Answer:
0.55
Explanation:
When multiplying values, the number of significant figures in the answer should be the same as the number with the lowest sig figs in the problem which in this case is 2 sig figs (0.17)
3.22 * 0.17 = .5474
Rounded to 2 sig figs = 0.55
