Question

The pressure of 1 mol of gas is decreased to 0.5 atm at 273 K. What happens to the molar volume of the gas under these conditions?

Answer 1

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

$PV=nRT$

where,

n = number of moles of gas  = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

$(0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)$

$V=44.82L$

Therefore, the molar volume of the gas will be, 44.82 L