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const2013 [10]
3 years ago
10

Compared to orange light, violet light

Chemistry
1 answer:
natulia [17]3 years ago
5 0

Answer:

i think it was lll,lV ㄸㄸㅇㅊㅎㅍㅋ

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An OH group attached to a hydrocarbon is called a _________ group whereas ______________ is a polyatomic ion with a charge of __
rodikova [14]

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3 0
3 years ago
Aisha drops an antacid tablet in water and times how long it takes to dissolve. Which of the following will decrease the reactio
madam [21]
1. Decreasing the temperature of the water.
2. One new atom with a large nucleus forms.
3.The reaction is an example of oxidation.
4 0
3 years ago
Read 2 more answers
AgNO3 + NaCl mc017-1.jpg NaNO3 + AgCl
lina2011 [118]

The balanced reaction is:

 AgNO3 + NaCl = NaNO3 + AgCl

 <span>We are given the amount of silver nitrate to react with sodium chloride. This will be our starting point.</span>

 15.0 mol AgNO3 (1 mol AgCl / 1 mol AgNO3 ) =15.0 mol AgCl


The amount of moles produced is the same with the amount of the given reactant since they only one is to one ratio.

8 0
4 years ago
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zvonat [6]

Answer:

Es Vendeis o puedes poner vendes

Explanation:

7 0
3 years ago
Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

  • The oxidation number of a free element is always zero.
  • The oxidation number of a monatomic ion equals the charge of the ion.
  • The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.
  • The oxidation number of  oxygen (O)  in compounds is usually -2.
  • The oxidation number of a Group 17 element in a binary compound is -1.
  • The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
  • The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) H_2SO_4

Let the oxidation state of 'S' be, 'x'

2(+1)+x+4(-2)=0\\\\x=+6

Hence, the oxidation state of 'S' is, (+6)

(b) Ca(OH)_2

Let the oxidation state of 'Ca' be, 'x'

x+2(-2+1)=0\\\\x=+2

Hence, the oxidation state of 'Ca' is, (+2)

(c) BrOH

Let the oxidation state of 'Br' be, 'x'

x+(-2)+1=0\\\\x=+1

Hence, the oxidation state of 'Br' is, (+1)

(d) ClNO_2

Let the oxidation state of 'N' be, 'x'

-1+x+2(-2)=0\\\\x=+5

Hence, the oxidation state of 'N' is, (+5)

(e) TiCl_4

Let the oxidation state of 'Ti' be, 'x'

x+4(-1)=0\\\\x=+4

Hence, the oxidation state of 'Ti' is, (+4)

(f) NaH

Let the oxidation state of 'Na' be, 'x'

x+(-1)=0\\\\x=+1

Hence, the oxidation state of 'Na' is, (+1)

4 0
3 years ago
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