Using the uniform distribution, it is found that:
A,B) 0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
C) 20% of the time does Josh’s bag arrive in less than 22 minutes.
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An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
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- In the graph, we have that the distribution is uniform between 20 and 30 minutes, thus

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Itens a and b:

0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
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Item c:
- Less than 22 minutes, thus:

0.2*100 = 20%
20% of the time does Josh’s bag arrive in less than 22 minutes.
A similar problem is given at brainly.com/question/15855314