All categories

3 years ago

What is the correct answer?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Welcome to the era of LeBron. If you thought he was doing the game a disservice by being a sore loser and egomaniac, you haven’t seen anything yet. It wasn’t enough that he decided to become a pariah, he and his group of cronies have decided they want to ruin the NBA.

How? By systematically turning every superstar in the NBA into LeBron James. They are trying to turn them into spoiled, delusional, lying, quitting cowards.

Two of the biggest stories this offseason have been the drama in Denver and New Orleans. Both players, for whatever reasons, have decided that they no longer want to be the cornerstone of a franchise. Before the summer of Lebron, neither had really been asking to get out of their situations. So what is the common thread here? Well, both are represented by agent Leon Rose. Who else is represented by Rose? Why Mr. James, of course.

You might be interested in

Identify the vertex of the graph tell weather it is minimum or maximum

Contact [7]

Vertex is (-2,-3) and it's a minimum.

4 0

2 years ago

Ms. Medina asked the class to solve the equation 2(x+4)=18.

7nadin3 [17]

Answer:

PEMDAS parentheses exponents multiplication divide add subtract....

4 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Add (-x + 4) + (3x + 2).

VashaNatasha [74]

Answer:

2x+6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the range of possible measures of x if each set of expressions represents measures of the sides of a triangle.

sergiy2304 [10]

Answer:

C. x > 3/2

Step-by-step explanation:

<u>According to the triangle inequality theorem, any side length is less than the sum of the other two:</u>

x < 2x + 1 + x + 4 ⇒ x < 3x + 5 ⇒ 2x > - 5 ⇒ x > - 2.5
2x + 1 < x + x + 4 ⇒ 2x + 1 < 2x + 4 ⇒ 1 < 4, any value of x
x + 4 < x + 2x + 1 ⇒ x + 4 < 3x + 1 ⇒ 2x > 3 ⇒ x > 3/2

<u>Common solution of the three inequalities above is:</u>

x > 3/2

Correct choice is C

8 0

2 years ago