We can use the compound interest formula
F=P(1+i)^n
where
F=Future value of investment to be found
P=present value of investment ($1000)
i=interest per period (1/4 year)=0.04/4=0.01
n=number of periods (3 years * 4 quarters = 12)
Substitute or "Plug in" values, so to speak,
F=1000*(1+0.01)^12
use a calculator to do the sum
=1126.83 (to the nearest cent, and use the proper rounding rules)
Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
its the first one
Step-by-step explanation:
Step-by-step explanation:
Quotient of 2/3 divided by 4
= (2/3) / 4
= 2/12
= 1/6.
The answer would be 6w^5y^3