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algol13
3 years ago
9

In an arithmetic​ sequence, the nth term an is given by the formula An=a1+(n−1)d​, where a1is the first term and d is the common

difference.​ Similarly, in a geometric​ sequence, the nth term is given by an=a1•rn−1.
Use these formulas to determine the indicated term in the given sequence.

The 19th term of 19​,42​,65​,88​,...
Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer: 433

Step-by-step explanation:

The given sequence : 19​,42​,65​,88​,...

We can see that the terms ha common difference as :-

42-19=23\\65-42=23\\88-65=23

Thus, its an Arithmetic progression with common difference (d)=23

The formula to find the nth term is :-

a_n=a_1+(n-1)d

Now, the 19th term of the given sequence :-

a_{19}=19+(19-1)(23)\\\\=19+(18)(23)\\\\=19+414=433

Hence, the 19th term of 19​,42​,65​,88​,... is 433.

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the percent of sales tax is 10%. what is the actual price of a pair of basketball shoes that cost $98?
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Answer:

(98/100)*110 = $107.8

Step-by-step explanation:

3 0
3 years ago
Which of the following is the line of symmetry for the figure shown below?
scoray [572]

Answer:

Line A

Step-by-step explanation:

A line of symmetry is a line that divides a shape into exactly two equal halves.

A triangle is a polygon with three sides and three angles. A scalene triangle has no lines of symmetry, an isosceles triangle has more than one line of symmetry while an equilateral triangle has three lines of symmetry.

From the diagram we can see that line A divides the figure into two equal halves, hence line A is the line of symmetry.

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3 years ago
A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

50 = 200 + C  ==>  C = -150

so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0
4 years ago
The Weschler Intelligence Scale for Children (WISC) is an intelligence test designed for children between the ages of 6 and 16.
Ostrovityanka [42]

Answer:

a) \bar X = 121.4

b) SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

c) 121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

Step-by-step explanation:

Data given: 126,111,141,96,123,115,116,113,127,114,122,116,104,126,126,132,139,111,143,121,119,107,154,125,120,135,142,132,94,103,143,115,132,107,118,105,101,135,94,153

Part a

For this case we can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And after replace we got:

\bar X = 121.4

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

For this case we assume that the population deviation is \sigma=15, we can calculate the standard error with this formula:

SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

Part c

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

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The distribution is skew
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