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2 years ago

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The length of each side of an equilateral triangle is increased by 5 inches, so the perimeter is now 60 inches. Write and solve

an equation to find the original length of each side of the equilateral triangle.

1 answer:

AfilCa [17]2 years ago

6 0

Answer:

The original length of each side of the equilateral triangle = x =15 inches

Step-by-step explanation:

Let Original length of side of equilateral triangle = x

If it is increased by 5 inches, the length will become = x+5

Since in equilateral triangle all the ides have same length so,

New Length of side 1 = x+5

New of side 2 = x+5

New Length of side 3 = x+5

Perimeter of triangle = 60 inches

We need to find the value of x

The formula used is: $Perimeter=Length \ of \ side \ 1 \ + Length \ of \ side \ 2 \ + Length \ of \ side \ 3$

Putting values in formula and finding x

$Perimeter=Length \ of \ side \ 1 \ + Length \ of \ side \ 2 \ + Length \ of \ side \ 3\\60=x+5+x+5+x+5\\60=3x+15\\60-15=3x\\45=3x\\x=\frac{45}{3}\\x=15$

So, the original length of each side of the equilateral triangle = x =15 inches

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b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

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e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

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Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

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$\mu = 128, \sigma = 23$

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{135 - 128}{23}$

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38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{141 - 128}{23}$

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71.30% probability that a person in China has blood pressure of 141 mmHg or less.

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X = 125

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X = 120

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 128}{23}$

$X - 128 = 1.28*23$

$X = 157.44$

So

157.44mmHg

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