Answer:
I think we need a graph to figure out this problem; the points need to be graphed. Otherwise, I do understand!
Given a N quantity of numbers, the Geometric Mean is equal to the N-th root of product of the N numbers
In this case, we have two numbers, then we need to multiply them and take square root:
![\sqrt{40\cdot15}=\sqrt[]{600}=\sqrt[]{100\cdot6}=\sqrt[]{100}\cdot\sqrt[]{6}=10\sqrt[]{6}](https://tex.z-dn.net/?f=%5Csqrt%7B40%5Ccdot15%7D%3D%5Csqrt%5B%5D%7B600%7D%3D%5Csqrt%5B%5D%7B100%5Ccdot6%7D%3D%5Csqrt%5B%5D%7B100%7D%5Ccdot%5Csqrt%5B%5D%7B6%7D%3D10%5Csqrt%5B%5D%7B6%7D)
The answer is:
10√6
Rounded is Approximately 24.5
Answer:
The answer is 81.
Step-by-step explanation:
Since the power of 4 is even, the result will be positive.
![{3}^{4}](https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B4%7D%20)
Simplify.
![81](https://tex.z-dn.net/?f=81)
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Answer:
a) n<1 and n>5
b) 0 < n < -4
c) n > 2 and n < -2
Step-by-step explanation:
The signal is given by x[n] = 0 for n < -1 and n > 3
The problem asks us to determine the values of n for which it's guaranteed to be zero.
a) x[n-2]
We know that n -2 must be less than -1 or greater than 3.
Therefore we're going to write down our inequalities and solve for n
![n-2](https://tex.z-dn.net/?f=n-2%3C-1%5C%5Cn%3C-1%2B2%5C%5Cn%3C1%5C%5C%5C%5Cn-2%3E3%5C%5Cn%3E5)
Therefore for n<1 and n>5 x [n-2] will be zero
b) x [n+ 3]
Similarly, n + 3 must be less than -1 or greater than 3
![n+30](https://tex.z-dn.net/?f=n%2B3%3C-1%5C%5Cn%3C-1-3%5C%5Cn%3C-4%5C%5C%5C%5Cn%2B3%3E3%5C%5Cn%3E3-3%5C%5Cn%3E0)
Therefore for n< -4 and n>0, in other words, for 0 < n < -4 x[n-2] will be zero
c)x [-n + 1]
Similarly, -n+1 must be less than -1 or greater than 3
![-n+13-1\\-n>2\\n](https://tex.z-dn.net/?f=-n%2B1%3C-1%5C%5C-n%3C-1-1%5C%5C-n%3C-2%5C%5Cn%3E2%5C%5C%5C%5C-n%2B1%3E3%5C%5C-n%3E3-1%5C%5C-n%3E2%5C%5Cn%3C-2)
Therefore, for n > 2 and n < -2 x[-n+1] will be zero
Answer:
Multiply each term in the first expression by each term in the second expression and combine like terms.
24a3+8a2+6a+4
Step-by-step explanation: