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Free_Kalibri [48]

4 years ago

12

F(x) = 4x² – 17x+3

1 answer:

Svet_ta [14]4 years ago

8 0

Answer:

discriminant: 241

2 real roots

Step-by-step explanation:

The discriminant is the part of the quadratic equation that is under the sqare root

x=(-b±√(b²-4ac))/2a

discriminant: b²-4ac

We also know that a quadratic equation is in the form ax²+bx+c = 0, so we can plug in the values we know from our equation to find the discriminant.

a=4

b=-17

c=3

(-17)^2-4(4)(3)

We also know that if the discriminant

is positive we have 2 real roots

is 0 we have 1 real root aka a repeated real solution

is negative we have no real roots

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The value in cents of 4 quarters and x dimes is

Zina [86]

To add numbers, their units should be the same. We need first to convert the quarters and dimes into cents.
4 quarters is equal to 100 cents, while a dime is equal to 10 cents.
In formula, the answer would be 100+10x. ( x refers to the number of dimes)

4 0

3 years ago

48 pens are packed in four boxes how many pens are packed in nine boxes

katovenus [111]

Answer:

108 pens

Step-by-step explanation:

48/4=x/9

4x=432

x=108

3 0

3 years ago

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I don't really know on this one. I'm thinking it's because if T kept going it would go into a 3rd quadrant but I'm not too sure.

enyata [817]

That is correct since the line in T is not straight it would eventually hit the third quadrant
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8 0

3 years ago

I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know

azamat

By definition of conditional probability,

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}$

$=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}$

Assuming a standard 6-sided fair die,

if $X_1=4$ , then $X_1+X_2=7$ means $X_2=3$ ; otherwise,
if $X_2=4$ , then $X_1=3$ .

Both outcomes are mutually exclusive with probability $\frac1{36}$ each, hence total probability $\frac2{36}=\frac1{18}$ .

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs $\frac6{36}=\frac16$ of the time.

Then the probability we want is

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13$

6 0

3 years ago

Which is the best estimate for 49% of 598 <br> A. 3 <br> B.30<br> C.300<br> D.3,000

DIA [1.3K]

Answer:

300

Step-by-step explanation:

3 would be extremely low

30 would be low

300 would be about right

3,000 lets not talk about this

Hope this helps

7 0

3 years ago

Read 2 more answers