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liraira [26]
3 years ago
15

Does the point (0, 0) satisfy the equation y = 9x?

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

yes it does

Step-by-step explanation:

because the equation y=9x does not have a y-intercept (all slopes come in the form y=mx+b -- it can be written differently though) and since there is no 'b' that means the y-intercept is 0. So whenever there is no y-intercept, the slope starts at 0.

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the third graph

Step-by-step explanation:

2x<6/÷2 we get x<3

3x+2>-4

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Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y = x squared + 2
Charra [1.4K]

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Step-by-step explanation:

y = x² + 2x - 5

d. D: all real numbers R: (y greater-than-or-equal-to negative 6)

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3 years ago
g 5. (5 points) Next, let’s turn our attention to the vector space P2, which is the set of polynomial with degree at most 2, tog
almond37 [142]

Answer:

No, those vectors do not span P₂

Step-by-step explanation:

At first, notice we have 4 vectors from a vector space of dimension 3 ({1,x,x²} is the standard base of P₂) so we are sure they are linearly dependent (because there are more than 3 vectors) i.e. it´s possible to write one of them in terms of other in the same set:

p4=p1-p2

(2x^{2} -x+1) - (x+3) = 2x^{2}-2x-2

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If we want to know the subspace that this span gets, we work with the matrix of the vectors made as follows:

A=\left[\begin{array}{ccc}1&3&5\\-1&1&-1\\2&0&4\end{array}\right]

The row-reduction of this matrix show us the basis of the same row-subspace even in the case that some of them are linearly dependent:

A\ is\ row--equivalent\ to:\left[\begin{array}{ccc}1&0&\frac{1}{2}\\0&1&-\frac{3}{2}}\\0&0&0\end{array}\right]

This shows that the span {p1,p2,p3}={(1+0.5x²),(x-1.5x²)}

Looking in the previous equality, the span {p1,p2,p3} is generated by two linearly independent vectors, but P₂ needs 3 linearly independent vectors to be generated.

The answer is that {p1,p2,p3,p4}⊂P₂.

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