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lozanna [386]
3 years ago
5

What additional information is required to prove that these two triangles are

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

none of the above

Step-by-step explanation:

I think you spamed the keyboard

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Please help . Really need done . Thank you . Will mark Brainly .
Gekata [30.6K]

Answer:

(5,2)

Step-by-step explanation:

Answer (5,2)

                         N(2)

W                                                  E(5)

                         S












8 0
3 years ago
In this particular arithmetic sequence, a8 = 28 and a16 = 108. What is the value of a24?
kap26 [50]
In this sequence d=10. Therefore, a24=188.
5 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
the price of the a tablet was increased from $180 to $207. by what percentage was the price of the tablet increased?
mixas84 [53]
207-180=27
27/180= .15
It was increased by 15%.
3 0
3 years ago
Read 2 more answers
Factor completely: x^2 - 5x - 6
Tom [10]

Answer:

x×x-5x-6

x × -4X - 6

Step-by-step explanation:

x×x-5x-6

x × -4X - 6

6 0
3 years ago
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