All categories

4 years ago

Which statement correctly explains how the Hertzsprung-Russell diagram helps to compare stars?

Physics

1 answer:

tekilochka [14]4 years ago

4 0

Answer:

The Hertzsprung-Russell diagram plots stars according to their luminosity and temperature, which is also associated with spectral class.

Explanation:

The Hertzsprung-Russell is a diagram representing:

- The surface temperature of the stars on the x-axis

- The absolute luminosity of the stars on the y-axis

So, the H-R diagram shows the relationship between the luminosity (power output) of a star and its temperature.

Most of the stars in the diagram are located along a diagonal line going from the top left to the bottom right: the stars in this diagonal are the stars in the main sequence, which is the main phase of life of a star.

Also, the graph shows that for stars in the main sequence, as the temperature increases, the luminosity also increases: these are the blue supergiant stars located in the top left corner.

Then, apart from the main sequence line, there are other groups of stars located in the top right corner (red giants) and in the bottom left corner (red, white dwarfs).

So, the correct answer is

The Hertzsprung-Russell diagram plots stars according to their luminosity and temperature, which is also associated with spectral class.

You might be interested in

Around what year can Carbon-14 dating be used up to and why?

Fofino [41]

Idk<span>Around what year can Carbon-14 dating be used up to and why?</span>

7 0

3 years ago

PLEASE HELP BRAINLIEST!!! 15 MIN!!!

N76 [4]

D.as a magnet is being thrust through the coil

5 0

3 years ago

Read 2 more answers

Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

$q = \lambda * L$

$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

Now using the above formula

$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

8 0

3 years ago

What is the acceleration of the object?<br> m/s²

Orlov [11]

Answer:

-2.5m/s^2

Explanation:

10-40/12-0=-2.5

7 0

2 years ago

The normal boiling point of water is 100.0 °c and its molar enthalpy of vaporization is 40.67 kj/mol. what is the change in entr

SashulF [63]

ΔS= nΔHvap/T,

Where, ΔS = Change in entropy, n = moles of water = 39.3/18 = 2.188 moles, ΔHvap = 40.67kJ/mol = 40670 J/mol, T = Temperature (K) = 100+272.15 = 373.15 K

Therefore,
ΔS = (2.188*40670)/373.15 = 237.96 J/K

6 0

3 years ago