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enyata [817]
4 years ago
5

Which statement correctly explains how the Hertzsprung-Russell diagram helps to compare stars?

Physics
1 answer:
tekilochka [14]4 years ago
4 0

Answer:

The Hertzsprung-Russell diagram plots stars according to their luminosity and temperature, which is also associated with spectral class.​

Explanation:

The Hertzsprung-Russell is a diagram representing:

- The surface temperature of the stars on the x-axis

- The absolute luminosity of the stars on the y-axis

So, the H-R diagram shows the relationship between the luminosity (power output) of a star and its temperature.

Most of the stars in the diagram are located along a diagonal line going from the top left to the bottom right: the stars in this diagonal are the stars in the main sequence, which is the main phase of life of a star.

Also, the graph shows that for stars in the main sequence, as the temperature increases, the luminosity also increases: these are the blue supergiant stars located in the top left corner.

Then, apart from the main sequence line, there are other groups of stars located in the top right corner (red giants) and in the bottom left corner (red, white dwarfs).

So, the correct answer is

The Hertzsprung-Russell diagram plots stars according to their luminosity and temperature, which is also associated with spectral class.​

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A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
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3 years ago
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An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100J of heat out of boiling
Alborosie

Answer:

Explanation:

Intake heat, QH = 100 J

output heat, Qc = 20 J

Work, W = 80 J

TH = 100°C = 373 K

Tc = 10°C = 283 K

TH/ Tc =  373 / 283 = 1.318

QH/Qc = 100 / 20 = 5

for a heat engine, those ratios should be same. so temperature is not correct.

4 0
4 years ago
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