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3 years ago

10

I need help please and thank you

2 answers:

I am Lyosha [343]3 years ago

6 0

Answer:

60

Step-by-step explanation:

Range is highest value minus lowest value. i.e 100-40=60

g100num [7]3 years ago

5 0

Put all the numbers is order then takeaway the smallest number from the highest

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This isn't really a school-related question.It's more of a conflict I have with my self. So: I have a friend that constantly cop

ycow [4]

Well to be honest, you need to straight forward to her and tell her that you do not appreciate her copying you and tell her you dont want to be rude or anything, but this needs to stop.

8 0

3 years ago

Find the perimeter of this shape

telo118 [61]

To find the circumference of a semi-circle, it would be 1/2<span> π × d. So, pi (3.14) times the diameter, 5 would be 15.7, but then we would need to multiply it by 1/2 to get the circumference for half the circle, and that will get you 7.85. Now you can add all the lengths now. 7.85 + 7 + 5 + 7 = 26.85. Hope this helps! Let me know if you still don't get it. <3</span>

7 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

4 years ago

Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)

Likurg_2 [28]

Answer:

$d = 14$

$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

<u>Step 3: Find Midpoint</u>

Substitute: $(\frac{5-9}{2},\frac{-1-1}{2})$
Subtract: $(\frac{-4}{2},\frac{-2}{2})$
Divide: $(-2,-1)$

7 0

3 years ago

Ms. Bell's mathematics class consists of 12 sophomores, 8 juniors, and 9 seniors. How many different ways can Ms. Bell create a

shtirl [24]

Answer:

792

Step-by-step explanation:

It's a combination question. The order is of no consequence. Also the fact that there are juniors and seniors is not important either.

So the answer is

12C5

12!

====

(12 - 5)! * 5!

12 * 11 * 10 * 9 * 8

==============

5 * 4 * 3 * 2 * 1

792

7 0

3 years ago