1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
Learn more about number of atoms at: brainly.com/question/8834373
#SPJ1
Answer:
Releases a lot of energy. When hydrogen a highly reactive element reacts with oxygen, it does so using immense force, when the bonds break high amounts of emery is released.
Explanation:
Lithium oxide is able to undergo both the processes of dissolution and dissociation.
Dissociation refers to the break down a chemical substance into its constituents. Ionization refers to the loss of electrons from a chemical specie while dissolving refers to the ability of a solid to form a solution.
Let us now look at each of the following species;
- Lithium oxide undergoes dissolution and dissociation.
- Magnesium nitride undergoes dissolution and dissociation.
- Hydrobromic acid undergoes dissolution and dissociation.
Learn more about ionization: brainly.com/question/1602374
Answer: 1.3% many crosslinks as isoprene units,
Explanation:
Given:
mass pf natural rubber= 200.0g
mass of sulphur = 4.8g
molar mass of sulphur =32g/mol
molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol
Solution: we first find no of moles present in each using
no of moles = 
Isoprene: 200.0g x [1mole / 68g] = 2.94moles.
Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.
to find % crosslinked units, we have
0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,
