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madam [21]
3 years ago
6

An adaptation allows an organism to _________________.

Chemistry
1 answer:
Elis [28]3 years ago
7 0

Answer:

Survive and reproduce.

Explanation:

Adpatation is the proccessof a organism devoloping new features in respone to a new enviroment.

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How many moles of oxide are in 0.050 g of Iron(III) oxide?
makvit [3.9K]

Answer:

0.00031311017345051

7 0
2 years ago
Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures? 12.0/7.11=?
xxMikexx [17]

Answer:

1.69.

Explanation:

  • The solution = 12.0 / 7.11 = 1.687 = 1.69.
  • The rule of significant figures for division states that: the results are reported to the fewest significant  figures.
  • 12.0 contains 3 significant figures.
  • 7.11 contains 3 significant figures.

So, the solution should contain 3 significant figures.

  • Now, the issue id of rounding; In a series of calculations, carry the extra digits through to  the final result, then round.
  • If the digit to be removed is equal to or greater than 5, the preceding digit is  increased by 1.
  • The digit that should be removed is 7 that is larger than 5 so increase the preceding digit by 1.
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3 years ago
Based on its chemical formula, which of the following substances is an organic compound
Tom [10]
I don't understand your question
6 0
3 years ago
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What is the value of the specific heat capacity of liquid water in j/mol·°c?
Scilla [17]
<span>he specific heat capacity of liquid water is 4.186 J/gm K.</span>
4 0
3 years ago
Read 2 more answers
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