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choli [55]
3 years ago
13

How many molecules are in 120 grams of Na2SO4

Chemistry
1 answer:
brilliants [131]3 years ago
5 0

3.06 × 10^23 molecules

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why when you mix three different colors the new color you see is brighter than the original colors you mixed
maria [59]

Answer:

Mixing colored lights & mixing colored paints. The primary colors of light are also known as the additive colors, because, when you add these three colors of light (red, green and blue) your brain perceives white light. The primary colors of paints, however, are known as subtractive colors.

Explanation:

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8 0
2 years ago
A volume of 75.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I
Evgesh-ka [11]

Answer: 17.78g

Explanation:

Assume there is no heat exchange with the environment, then the amount of heat taken by the steel rod, Q(s), is equal to the amount of heat lost by the water, Q(w), but with opposite sign.

Q(s) = -Q(w)

Remember, Q = mc(ΔΦ)

Where Q = amount of heat

m = mass of steel

c = specific heat capacity of steel

ΔΦ = Initial temperature T1 - Final temperature T2

Q = mc(T1-T2)

Recall, Q(s) = -Q(w). Then,

m(s)*c(s)*(T1s - T2s) = - m(w)*c(w)*(T1w - T2w)

Substituting each values

Note: m(w) = volume of water*density = 75mL*1g/mL = 75g

m(s)*0.452*(21.5-2) = -75*4.18*(21.5-22)

m(s)*8.814 = 156.75

m(s) = 156.75/8.814

m(s) = 17.78g

Therefore, the mass of steel is 17.78g

8 0
3 years ago
Which is true of oxidation
irakobra [83]

Answer:

D

Explanation:

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3 0
2 years ago
Read 2 more answers
Which of the following statements is not accurate? A. At constant temperature, halving the number of gas particles in a given sp
vlabodo [156]
I suggest you to go with C !! it is absolutely wrong sentence !!

increasing the gas particles will increase the collision between them so !!

your answer is C !!
4 0
3 years ago
Read 2 more answers
How many joules of heat must be transferred to a 480-g aluminum pizza pan to raise its temperature from 22C to 234C? The specifi
NemiM [27]
The given formula for heat, Q=mc(Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.

Q = mc(Tf-Ti) = 480g(0.96 J/g-C)(234-22) = 97689.6 Joules of heat
6 0
3 years ago
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