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3 years ago

Is CaC1 a ionic , Polar covalant or non polar covalent ?

Chemistry

1 answer:

patriot [66]3 years ago

5 0

Polar Covalent.

This is because both Calcium (Ca) and Carbon (C) are non metals, thus eliminating the ionic option.

It is polar covalent rather than nonpolar covalent due to the fact that the electrons in a polar covalent bond are shared unequally while those in a nonpolar bond are shared equally.

This can be determined by looking at the amount of valence electrons; if the electrons cancel each other out, it is shared equally. If not, it is shared unequally.

Hope this helps!

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Brainlist for best answer!!! Why will the whole ecosystem be affected by just one change?

Naddika [18.5K]

Answer:

Critical coordinate drivers incorporate living space alter, climate alter, obtrusive species, over exploitation, and contamination. Most of the coordinate drivers of corruption in biological systems and biodiversity right now stay steady or are developing in escalated in most biological systems.

Explanation:

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3 years ago

Read 2 more answers

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

djverab [1.8K]

Answer:

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=P_1=13.2 Torr$

Partial pressure of the $Cl_2=P_2=13.2 Torr$

Partial pressure of the $PCl_5=P_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{P_1}{P_1\times P_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=P_1'=13.2 Torr$

Partial pressure of the $Cl_2=P_2'=?$

Partial pressure of the $PCl_5=P_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=P_1'+P_2'+P_3'$

$263.0Torr=13.2 Torr+P_2'+217.0 Torr$

$P_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{P_3'}{P_1'\times P_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

5 0

3 years ago

Calcium Oxide will react with ammonium chloride to produce ammonia gas, water vapor, and calcium chloride. If only 16.3 g of amm

Vaselesa [24]

Answer:

%age Yield = 22.72 %

Explanation:

The balance chemical equation is as follow;

2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O

Step 1: Calculate Moles of CaO, NH₄Cl and NH₃;

CaO:

Moles = Mass / M.Mass

Moles = 112 g / 56.07 g/mol

Moles = 1.99 moles of CaO

NH₄Cl:

Moles = Mass / M.Mass

Moles = 224 g / 53.49 g/mol

Moles = 4.18 moles of NH₄Cl

NH₃:

Moles = Mass / M.Mass

Moles = 16.3 g / 17.03 g/mol

Moles = 0.95 moles of NH₃

Step 2: Calculate Limiting reagent as:

According to equation.

2 moles of NH₄Cl reacts with = 1 mole of CaO

So,

4.18 moles of NH₄Cl will react with = X moles of CaO

Solving for X,

X = 4.18 mol × 1 mol / 2 mol

X = 2.09 mol of CaO

This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.

Step 3: Calculate Theoretical Yield of NH₃ as;

According to equation.

2 moles of NH₄Cl produced = 2 moles of NH₃

So,

4.18 moles of NH₄Cl will produce = X moles of NH₃

Solving for X,

X = 4.18 mol × 2 mol / 2 mol

X = 4.18 mol of NH₃

Step 4: Calculate Percentage Yield as;

%age Yield = Actual Yield / Theoretical Yield × 100

%age Yield = 0.95 mol / 4.18 × 100

%age Yield = 22.72 %

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3 years ago

Choose all the answers that apply.

agasfer [191]

Answer:

hydrogen are converted into energy I dont know other

7 0

3 years ago

If you had 2.50 moles of anything, how many of those things would you have?

Wittaler [7]

Answer:

1.51 x 10²⁴ things

Explanation:

According to Avogadro's Constant.

1 mole of any substance, constains 6.02×10²³ particles of that subtance.

From the question,

If we have 2.50 moles of anything,

1 mole of anything ⇒ 6.02×10²³ things

2.50 moles of anything ⇒ y things

solving for y

y = (2.50× 6.02×10²³)/1

y = 15.05×10²³

y = 1.505×10²⁴

y ≈ 1.51×10²⁴

7 0

3 years ago