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Monica [59]
3 years ago
9

A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during

the rotation?
A.) 1
B.) 2
C.) 4
D.) 8
Mathematics
2 answers:
ycow [4]3 years ago
4 0
Given that the octagon rotates 360 degrees, it is a given that for every regular division of the polygon (360/8 = 45 degrees), the image would coincide with the pre-image during the rotation. Therefore, the octagon would coincide a total of 8 times as it rotates 360 degrees about its center. 
S_A_V [24]3 years ago
4 0

Answer:

8

Step-by-step explanation:

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Question
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lina2011 [118]
<h3>Answer:</h3>

System

  • p + m = 10
  • 0.8m = 0.4·10

Solution

  • p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>Step-by-step explanation:</h3>

(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.

For the total amount of mix:

... p + m = 10

For the quantity of peanuts in the mix:

... p + 0.2m = 0.6·10

For the quantity of almonds in the mix:

... 0.8m = 0.4·10

For the ratio of peanuts to almonds:

... (p +0.2m)/(0.8m) = 0.60/0.40

Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.

So, your system of equations could be ...

  • p + m = 10
  • 0.8m = 0.4·10

___

(b) Dividing the second equation by 0.8 gives

... m = 5

Using the first equation to find p, we have ...

... p + 5 = 10

... p = 5

5 lb of peanuts and 5 lb of mixture are required.

8 0
3 years ago
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