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3 years ago

9

A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during

the rotation?
A.) 1
B.) 2
C.) 4
D.) 8

2 answers:

ycow [4]3 years ago

4 0

Given that the octagon rotates 360 degrees, it is a given that for every regular division of the polygon (360/8 = 45 degrees), the image would coincide with the pre-image during the rotation. Therefore, the octagon would coincide a total of 8 times as it rotates 360 degrees about its center.

S_A_V [24]3 years ago

4 0

Answer:

8

Step-by-step explanation:

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SOMEONE HELP QUESTION 1 PLZZZZO

leva [86]

Answer:

A) 370

Explanation:

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3 years ago

The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

$Volume = Length\times height\times width$

Substitute all given value in above formula.

$258.75 = (h-4)\times h\times 3$

Rewrite the equation as:

$258.75 = 3h(h-4)$

$258.75 = 3h^2-12h$

$3h^2-12h-258.75=0$

whole equation divided by 3.

$h^2-4h-86.25=0$

Use quadratic formula with $a = 1, b = -4,c=-86.25$

$h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put these a, b and c value in above equation.

$h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}$

$h=\frac{4\pm \sqrt{16+345}}{2}$

$h=\frac{4\pm \sqrt{361}}{2}$

$h=\frac{4\pm 19}{2}$

For positive sign

$h=\frac{23}{2}$

h = 11.5 in

For negative sign

$h=\frac{-15}{2}$

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

4 0

3 years ago

Im really struggling with these questions can anyone help me?

Alchen [17]

Q1
the clothes are on 45% discount, wich mean they become 55% of their original price.

30× 55% =16.5
64×55%=35.2

the new salary is 103% of the original

10×103% = 10.3
11600×103% = 11,948

Q2:

1+0.24= 1.24
1- 0.27= 0.73

86×140%= 120.4
440×119%= 523.6
82×90% = 73.8
480× 73%= 350.4

8 0

3 years ago

A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multi

Ierofanga [76]

Answer: A. Factor 2 => 4x greater

Factor 3 => 9x greater

Factor 5 => 25x greater

Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:

A = 2.π.r.h

A cylinder of radius r and height h has area:

$A_{1}$ = 2πrh

If multiply both dimensions <u>by a factor of 2</u>:

$A_{2}$ = 2.π.2r.2h

$A_{2}$ = 8πrh

Comparing $A_{1}$ to $A_{2}$ :

$\frac{A_{2}}{A_{1}}$ = $\frac{8.\pi.rh}{2.\pi.rh}$ = 4

Doubling radius and height creates a surface area of a cylinder 4 times greater.

<u>By factor 3:</u>

$A_{3} = 2.\pi.3r.3h$

$A_{3} = 18.\pi.r.h$

Comparing areas:

$\frac{A_{3}}{A_{1}}$ = $\frac{18.\pi.r.h}{2.\pi.r.h}$ = 9

Multiplying by 3, gives an area 9 times bigger.

<u>By factor 5</u>:

$A_{5} = 2.\pi.5r.5h$

$A_{5} = 50.\pi.r.h$

Comparing:

$\frac{A_{5}}{A_{1}}$ = $\frac{50.\pi.r.h}{2.\pi.r.h}$ = 25

The new area is 25 times greater.

B. By analysing how many times greater and the factor that the dimensions are multiplied, you can notice the increase in area is factor². For example, when multiplied by a factor of 2, the new area is 4 times greater.

3 0

3 years ago

What is the ratio for 12:75

adoni [48]

It would be: 12/75 = 4/25

So, your answer is 4/25

6 0

3 years ago