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3 years ago

In ΔABC, what is the measure of angle B?

Mathematics

2 answers:

DiKsa [7]3 years ago

6 0

This theorem says that the exterior angle is equal to the sum of its remote interior angles. In other words, 140 = 2x + x + 2. 140 = 3x + 2 and 138 = 3x. Therefore, x = 46. Multiply it by 2 to get angle B is 92 degrees.

Lyrx [107]3 years ago

4 0

Answer:

The Answer is 92

Step-by-step explanation:

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SOOO I NEED SOME HLP HERE PLSSSS

jek_recluse [69]

Answer:

Step-by-step explanation:

you just have to mirror it to the other side. so K lands on (4, 1)

6 0

2 years ago

Ms. MacArthur surveyed students to find the amount of time they spent reading and watching TV last week. The scatter plot below

ivann1987 [24]

Answer:

No, because James has confused the hours of watching tv with the hours of reading.

Step-by-step explanation:

This is incorrect. According to the graph, what we have is a point on the line at (6, 10), which implies that a student who reads for 6 hours will watch tv for 10 hours.

It is very likely that James is confusing the hours of watching tv with the hours of reading.

4 0

3 years ago

Assume that a sample is used to estimate a population proportion p. Find the 95% confidence for a sample of size 246 with 52% su

denpristay [2]

Using the z-distribution, the 95% confidence interval for the proportion is given as follows:

(0.4576, 0.5824).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters for the interval are given as follows:

$n = 246, \pi = 0.52$ .

The lower and upper bound of the interval, respectively, are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 - 1.96\sqrt{\frac{0.52(0.48)}{246}} = 0.4576$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 + 1.96\sqrt{\frac{0.52(0.48)}{246}} = 0.5824$

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0

2 years ago

A rocket is fired upward from some initial distance above the ground. Its height (in feet), h, above the ground t seconds after

I am Lyosha [343]

Answer:

the object will attain maximum height at 3.5 seconds.

Step-by-step explanation:

The height of the object (in feet), h, above the ground t seconds after it is fired is given by h(t)=−16t2+112t+128.

128 represents 128 feet above the ground and this is the height from which the object was fired.

The given equation is a quadratic equation and plotting of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the object will attain maximum height at 3.5 seconds.

7 0

3 years ago

What is the perimeter of angle DEF to the nearest tenth of a unit?<br> helppppp<br> tysm

hammer [34]

<h3>Answer: 36.4 units (choice A)</h3>

===========================================================

Explanation:

Let's use the distance formula to find the distance from D to E

$D = (x_1,y_1) = (-7,2) \text{ and } E = (x_2, y_2) = (3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-7-3)^2 + (2-4)^2}\\\\d = \sqrt{(-10)^2 + (-2)^2}\\\\d = \sqrt{100 + 4}\\\\d = \sqrt{104}\\\\d = \sqrt{4*26}\\\\d = \sqrt{4}*\sqrt{26}\\\\d = 2\sqrt{26}\\\\d \approx 10.198\\\\$

Note: uppercase D refers to the point, while lowercase d is the distance from D to E.

The length of segment DE is roughly 10.198 units long.

----------------

Repeat for the distance from E to F.

$E = (x_1,y_1) = (3,4) \text{ and } F = (x_2, y_2) = (5,-7)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (4-(-7))^2}\\\\d = \sqrt{(3-5)^2 + (4+7)^2}\\\\d = \sqrt{(-2)^2 + (11)^2}\\\\d = \sqrt{4 + 121}\\\\d = \sqrt{125}\\\\d = \sqrt{25*5}\\\\d = \sqrt{25}*\sqrt{5}\\\\d = 5\sqrt{5}\\\\d \approx 11.1803\\\\$

Segment EF is roughly 11.1803 units long.

----------------

Repeat for the distance from F to D.

$F = (x_1,y_1) = (5,-7) \text{ and } D = (x_2, y_2) = (-7,2)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(5-(-7))^2 + (-7-2)^2}\\\\d = \sqrt{(5+7)^2 + (-7-2)^2}\\\\d = \sqrt{(12)^2 + (-9)^2}\\\\d = \sqrt{144 + 81}\\\\d = \sqrt{225}\\\\d = 15\\\\$

Unlike the others, this result is exact.

----------------

Add up the three segment lengths to get the perimeter

DE + EF + FD

10.198 + 11.1803 + 15

36.3783

The perimeter is approximately 36.3783 units which rounds to <u>36.4</u>

The answer has been confirmed with GeoGebra.

4 0

2 years ago