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3 years ago

In ΔABC, what is the measure of angle B?

Mathematics

2 answers:

DiKsa [7]3 years ago

6 0

This theorem says that the exterior angle is equal to the sum of its remote interior angles. In other words, 140 = 2x + x + 2. 140 = 3x + 2 and 138 = 3x. Therefore, x = 46. Multiply it by 2 to get angle B is 92 degrees.

Lyrx [107]3 years ago

4 0

Answer:

The Answer is 92

Step-by-step explanation:

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An equation of the line that passes through the points (3,5) and (6,7) in point-slope form

Oliga [24]

Answer:

y-5=1/4(x-3)

Step-by-step explanation:

first you need to find the slope.

5-7 over 3-6 = -1/-4 or 1/4

next put into point-slope form.

y-y1=m(x-x1)

or y-5=1/4(x-3)

7 0

3 years ago

Solve kx-2=7 for x. A. x=5/k B. x=9k C. x=9-k D. x=9/k

timurjin [86]

Answer:

the answer is D- 9/k

8 0

1 year ago

Read 2 more answers

Angle M and Angle N are vertical angles. The measure of Angle M is 3x – 18. The measure of Angle N is x + 30.

torisob [31]

Answer:

$24 = x$

$54° = Measure\:of\:Angle\:N$

$54° = Measure\:of\:Angle\:M$

Step-by-step explanation:

Vertical Angles are congruent, so set the two expressions equal to each other:

[x + 30]° = [3x - 18]°

-[3x]° - [3x]°

___________

−18° = 30° - [2x]°

- 30° - 30°

____________

−48° = [−2x]°

____ ___

−2° −2°

$24° = x$ [Plug this back into both expressions to get both m∠N and m∠M at 54°.]

I am joyous to assist you anytime.

5 0

3 years ago

An arithmetic sequence is defined by the general term tn = -5 + (n - 1)78, where n ∈N and n ≥ 1. What is the recursive formula o

GrogVix [38]

$\text{The general term of an arithmetic sequence:}\ a_n=a_1+(n-1)d\\\\a_n-n-th\ term\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ t_n=-5+(n-1)78.\ \text{Therefore}\ t_1=-5\ \text{and}\ d=78\\\\\text{The recursive formula of the sequence:}\\\\\left\{\begin{array}{ccc}t_1=-5\\t_n=t_{n-1}+78\end{array}\right$

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2 years ago

What is the greatest common factor of 20x6y+40x4y2−10x5y5 ?

mestny [16]

The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
20x^6y = 10x^4y*2x^2
40x^4y^2 = 10x^4y*4y
10x^5y^5 = 10x^4y*y^4

8 0

3 years ago