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Artemon [7]
2 years ago
11

Solve and check: -9k+13+k=61

Mathematics
2 answers:
VARVARA [1.3K]2 years ago
8 0
-8k= 48

divide 8

ANSWER: k = -6
olga nikolaevna [1]2 years ago
6 0

\text{Solve for k:}\\\\-9k+13+k=61\\\\\text{Combine like terms:}\\\\-8k+13=61\\\\\text{Subtract 13 from both sides}\\\\-8k=48\\\\\text{Divide both sides by -8}\\\\\boxed{k=-6}

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-2x-9y=-25 -4x-9y=-23 system with elimination
REY [17]
Multiply the first equation by -2. It turns into 4x+18y=50 and the other one stays -4x-9y=-23. Then you "eliminate" the equations by "adding" them. Set it up like this: 
4x+18y=50
      +
-4x-9y=-23
4x-4x= 0. 18y-9y= 9y and 50-23= 27
SO: 9y= 27 and y= 3
And then you plug that in to one equation: 4x +18(3)= 50. 4x= 50-(18*3)
4x= -4, so x=-1.
Plug it back in to check! 
Hope this helps. Happy solving! :)
4 0
2 years ago
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zhenek [66]
No because (0,1) isn't a solution for both equations. It is for the first one, but not the second.


please vote my answer brainliest. thanks!
4 0
3 years ago
What is 22 hundredths as a decimal ?
Schach [20]
.022 would be 22 hundredths as a decimal
8 0
2 years ago
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When adding two numbers, such as 123 and 423, care is taken to first line them up and then add like digits. How does expanding t
zavuch27 [327]
Think of 10^2, 10^1, and 10^0 as x^2, x^1, and x^0.
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When you add expanded numbers, you can only combine like powers of 10.

123 + 423 =

= (100 + 20 + 3) + (400 + 20 + 3)

= (1 * 10^2 + 2 * 10^1 + 3 * 10^0) + (4 * 10^2 + 2 * 10^1 + 3 * 10^0)

= (1 * 10^2 + 4 * 10^2) + (2 * 10^1 + 2 * 10^1) + (3 * 10^0 + 3 * 10^0)

= 5 * 10^2 + 4 * 10^1 + 6 * 10^0

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7 0
2 years ago
PLEASE HELP! (Needs to be graphed)
erma4kov [3.2K]

Answer:

answer is 25

Step-by-step explanation:

25 times 4

3 0
3 years ago
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