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grigory [225]
4 years ago
10

F(x)=4x^5-8x^4-5x^3+10x^2+x-2

Mathematics
1 answer:
Vaselesa [24]4 years ago
6 0

Answer:

-1; -1/2; 1/2; 1; 2          or    factors of -2 are -1, 2, 1, -2

factors of 4 are 1, 4, 2, -1, -4, -2

possible zeros are -1, 1, 1/2, -1/2

try 1

Step-by-step explanation:

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Please help me with this
Serga [27]

Answer:

11 sq.ft

Step-by-step explanation:

∅= 80×π/180= 4π/9

area= 1/2 × r²× ∅

= 1/2 × 16 × ∅

= 8∅

=8×(4π/9)

= 32π/9

= 11.17 ~11

6 0
3 years ago
I NEED HELP WITH 5,6,7,8
NARA [144]

Answer:

2,78,10,7

Step-by-step explanation:

3 0
3 years ago
Prove that: (Sec A- cosec A)(1+ tan A+cot A) = tan A× sec A - cot A × cosec A
mash [69]

Answer:

Step-by-step explanation:

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA

we take the LHS so here goes,

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA\\(\frac{1}{cosA} -\frac{1}{sinA})(1+\frac{sinA}{cosA}+\frac{cosA}{sinA})\\\\(\frac{sinA-cosA}{sinAcosA})(\frac{sinAcosA+sin^2A+cos^2A}{sinAcosA})\\

since , sin^2A+cos^2A=1

the identity becomes,

(\frac{sinA-cosA}{sinAcosA})(\frac{1+sinAcosA}{sinAcosA})\\\\(\frac{sinA+sin^2AcosA-cosA-cos^2AsinA}{sin^2Acos^2A})\\\\

now, we know,

sin^2A=1-cos^2A and cos^2A=1-sin^2A

the identity becomes,

(\frac{sinA+(1-cos^2A)cosA-cosA-(1-sin^2A)sinA}{sin^2Acos^2A} )\\\\

(\frac{sinA+cosA-cos^3A-cosA-sinA+sin^3A}{sin^2Acos^2A})

sin A and cos A cancel out it becomes zero

\frac{sin^3A-cos^3A}{sin^2Acos^2A} \\\\

Splitting the denominator the identity becomes

\frac{sin^3A}{sin^2Acos^2A}-\frac{cos^3A}{sin^2Acos^2A}  \\\\\frac{sinA}{cos^2A} - \frac{cosA}{sin^2A} \\\\\frac{sinA}{cosA}(\frac{1}{cosA})-\frac{cosA}{sinA}(\frac{1}{sinA})\\\\

Hence,

tanAsecA-cotAcosecA

3 0
3 years ago
Margie received her store order on 12/3/16 at 4AM. She just opened one of the
Cerrena [4.2K]

Answer:

Exp Date: 1/17/2017

Exp Time: 4:00am

Prep Date: 12/3/2016

Prep Time: 4:00am

Initials: 12/7/2016

Step-by-step explanation:

A well-detailed version of the question has been uploaded in form of an image for easier understand.

Looking at the question, it was said that she received her store order on 12/3/2016 at 4am, this implies that the prep date and time are 12/3/2016 and 4am respectively. Also, it was said that the expiration date was printed on the product and it is 1/17/2017. Obviously, the expiration time would also be 4am because it was prepared at 4am and if we calculate in. 24hours we would get 4am at the expiration date as well. Lastly, we were told she opened the product she received on 12/7/2016 which is the initial date the product was used. From all these we can deduce the following:

Exp Date: 1/17/2017

Exp Time: 4:00am

Prep Date: 12/3/2016

Prep Time: 4:00am

Initials: 12/7/2016

8 0
3 years ago
What’s the slope of (-2,1) and (3,-3)
dybincka [34]

Answer:

-4/5

Step-by-step explanation:

slope = m = (difference in y)/(difference in x) = (-3 - 1)/(3 - (-2)) =-4/5

4 0
4 years ago
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