I NEED HELP WITH 5,6,7,8

Jeremy bakes two pans of brownies that are the same size. One pan has nuts in it and the other pan does not. He cuts the pan wit

MAVERICK [17]

Answer:

The answer is " $\frac{2}{8} > \frac{3}{16}$ So, they eat more brownies with nuts".

Step-by-step explanation:

In the given question, the two browny pans of equal size are baked by Jeremy. There is indeed a saucepan with nuts in it, not the other pan. He split the pot into eight equal chunks with nuts. He slices the pan into 16 equal parts without nuts. His mates eat 2 nuts brownies and three nut-free brownies. They eat more nuts and brownies $\frac{2}{8} > \frac{3}{16}$ eat more.

5 0

3 years ago

How many times does the graph of the function below intersect touch the x-axis? y= -3x^2 + x + 4

inessss [21]

Answer:

2 times

Step-by-step explanation:

Well let's first graph the quadratic equation,

Look at the image below ↓

By looking at the image below we can tell that the graph touches the x axis 2 times at,

<em />

<em>the parabola touches the x axis twice.</em>

<em />

<em>Hope this helps :)</em>

6 0

3 years ago

What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?

denis23 [38]

The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):
$d^2 = (x-x_0)^2 + (y-y_0)^2$
Plugging in points A and B into distance formula, then setting them equal to each other gives:
$(x-2)^2+(y-6)^2 = (x-2)^2 + y^2$
Right away we can cancel out the x terms leaving:
$(y-6)^2 = y^2$
Expand Left side and Solve for y:
$y^2 -12y +36 = y^2$
$y = 3$
Plug in points B and C as before:
$(x-2)^2 + y^2 = (x-10)^2 + y^2$
Here we can cancel the y-terms.
Expand and solve for x:
$x^2 -4x+4 = x^2 -20x+100$
$16x = 96$
$x = 6$
Therefore the center of the circle is the point (6,3)

6 0

4 years ago

A study was conducted to compare the proportion of drivers in Boston and New York who wore seat belts while driving. Data were c

In-s [12.5K]

(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

A.)

According to given data find the test statistic for this test using Ha:

p1 = 0.581

p2 = 0.832

standard error = SE = 0.116

<h3>Test statistics :-</h3>

Z = $\frac{p1 - p2}{SE}$

Z = $\frac{0.581 - 0.832}{0.116}$ = -2.164

Z = -2.164

B.)

According to given Determine the p-value (3 decimal places).

<h3>p - value</h3>

it is left tailed test.

p - value for left tailed test is,

p - value = P(Z < test statistics )

p - value = P(Z < -2.164)

P - value = 0.015

C.)

Based on this p-value, which of the following would you expect for a 95%

confidence level = 95% = 0.95

significance level = α = 0.05

P -value is less than 0.05

so, reject null hypothesis at α = 0.05

That is $P_{B}$ < $P_{NY}$

so, based on P - value , All values in the 95% confidence interval

PB - PNY is negative.

D.)

According to given data What is the correct conclusion?

Reject null hypothesis at α = 0.05

so, $P_{B}$ < $P_{NY}$

Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

know more about test statics visit this link

brainly.com/question/23332597

#SPJ4

3 0

2 years ago

a can has 50 marbles in it. Every hour, 7 marbles are taken out.After 4hours, how many marbles are left in the can?

KengaRu [80]

7×4=28

now subtract:

50-28=22

there are 22 marbles left in the can

hope this helped

5 0

4 years ago