Answer:
If you take it in terms of integers,
9+3v may or may not be greater or equal to 6. It depends on the value of the variable you put in.
For eg:- if you substitute the value for v as 2 then 9+3x2=15 which is greater than 6 but if you put in -1 for v then you will get 9+3x(-1)=6
Answer: idk the first equation
Step-by-step explanation:
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
<h2>1.</h2>
Firstly, combine like terms: 
Next, subtract r on both sides of the equation: 
Next, add 8 onto both sides of the equation: 
Lastly, divide both sides by 6 and <em><u>your answer will be r = 3.</u></em>
<h2>2.</h2>
Firstly, multiply both sides by e: 
Lastly, divide both sides by 3, and <em><u>your answer will be
</u></em>